We have gravity here on earth while in space there’s none
Answer: 4.22 grams of solute is there in 278 ml of 0.038 M 
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
where,
n = moles of solute
= volume of solution in L
Now put all the given values in the formula of molality, we get
mass of = 
Thus 4.22 grams of solute is there in 278 ml of 0.038 M
Answer:
The correct answer is C.
Explanation:
To solve this problem, we should first recall possible units for mass and volume. Mass can be represented with units of grams, kilograms, etc. Volume has units of cubic meters, cubic centimeters, etc.
Therefore, since we know that density is mass divided by volume, the only answer that makes sense here is C. grams per cubic centimeter (where per signifies that grams are being divided by cubic centimeters).
Hope this helps!
Answer:
0.100 M AlCl₃
Explanation:
The variation of boiling point by the addition of a nonvolatile solute is called ebullioscopy, and the temperature variation is calculated by:
ΔT = W.i
Where W = nsolute/msolvent, and i is the Van't Hoff factor. Because all the substances have the same molarity, n is equal for all of them.
i = final particles/initial particles
C₆H₁₂O₆ don't dissociate, so final particles = initial particles => i = 1;
AlCl₃ dissociates at Al⁺³ and 3Cl⁻, so has 4 final particles and 1 initial particle, i = 4/1 = 4;
NaCl dissociates at Na⁺ and Cl⁻ so has 2 final particles and 1 initial particle, i = 2/1 = 2;
MgCl₂ dissociates at Mg⁺² and 2Cl⁻, so has 3 final particles and 1 initial particle, i = 3/1 = 3.
So, the solution with AlCl₃ will have the highest ΔT, and because of that the highest boiling point.
Answer:
Explanation:
Hello,
In this case, by using the Avogadro's law which allows us to understand the volume-moles behavior as a directly proportional relationship:
We can compute the volume of 34.3 g of argon by representing it in mole as shown below:
Thus, we find:
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