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4 years ago

How do I balance Hg(NO3)2

Chemistry

2 answers:

yKpoI14uk [10]4 years ago

8 0

I believe that it’s 2Hg(NO3)2=2HgO+4NO2+O2 correct me if i am wrong

lys-0071 [83]4 years ago

7 0

There is no equation

Explanation:

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Organisms that are producers

goldfiish [28.3K]

Answer:

Grass, trees, and flowers.

Explanation:

A producer converts the suns energy to make its own food, and a producer uses photosynthesis.

7 0

3 years ago

The value of the equilibrium constant K depends on: I. the initial concentrations of the reactants. II. the initial concentratio

Elden [556K]

Answer:

None of these

Explanation:

For a reaction;

aA + bB ------>cC + dD

The equilibrium constant K is given as;

K = [C]^c [D]^d/[A]^a [B]^b

The equilibrium constant neither depends on the concentrations of the reactants nor on that of the products.

Let us recall that at equilibrium, the concentrations of reactants and products remain largely constant. This implies that, concentration of species do not appreciably change at equilibrium because the rates of forward and reverse reactions are equal.

Hence, the equilibrium constant neither depends on the initial/final concentrations of the reactants nor on the initial/final concentrations of the products.

4 0

3 years ago

KE and PE Math

slava [35]

Answer:

1. Answer: The bowling ball has more potential energy as it sits on top of the building. It does not have any kinetic energy because it is not moving.

2. Answer: The bowling ball has equal amounts of potential and kinetic energy half way through the fall. At the half way point, half of the potential energy has been converted to kinetic energy.

3. Answer: Just before the ball hits the ground, it has more kinetic energy. As it hits the ground the potential energy becomes zero.

4. Answer:

PE=784 J

5. Answer:

PE = 392 J

6. Answer:

KE= 392 J

Also, since the PE and KE are equal at the half way point and PE =392 J, KE = 392 J.

7. What is the kinetic energy of the ball just before it hits the ground?

Answer:

KE=784 J

At first I answered in the comments, but I am able to answer now. I hope this can help

6 0

4 years ago

A student mixes in a test tube 3.00mL of 0.050M CuSO4with 7.00mL of 0.20M NH3/NH41 . The solution becomes a deep blue color. Ass

valkas [14]

Answer:

$\large \boxed{\text{0.0035 mol/L}}$

Explanation:

We are given the volumes and concentrations of two reactants, so this is a limiting reactant problem.

We know that we will need moles, so, lets assemble all the data in one place.

Cu²⁺ + 4NH₃ ⟶ Cu(NH₃)₄²⁺

V/mL: 3.00 7.00

c/mol·L⁻¹: 0.050 0.20

1. Identify the limiting reactant

(a) Calculate the moles of each reactant

$\text{Moles of Cu}^{2+}= \text{3.00 mL solution} \times \dfrac{\text{0.050 mmol Cu}^{2+}}{\text{1 mL solution}} = \text{0.150 mmol Cu}^{2+}\\\\\text{Moles of NH}_{3} = \text{7.00 mL solution} \times \dfrac{\text{0.20 mmol NH}_{3}}{\text{1 mL solution}} = \text{0.140 mmol NH}_{3}$

(b) Calculate the moles of Cu(NH₃)₄²⁺ that can be formed from each reactant

(i) From Cu²⁺

$\text{Moles of Cu(NH$_{3}$)$_{4}$$^{2+}$} = \text{0.150 mmol Cu}^{2+} \times \dfrac{\text{1 mmol Cu(NH$_{3}$)$_{4}$$^{2+}$}}{\text{1 mmol Cu}^{2+}}\\\\= \text{0.150 mmol Cu(NH$_{3}$)$_{4}$$^{2+}$}$

(ii) From NH₃

$\text{Moles of Cu(NH$_{3}$)$_{4}$$^{2+}$} = \text{0.140 mmol NH}_{3} \times \dfrac{\text{1 mmol Cu(NH$_{3}$)$_{4}$$^{2+}$}}{\text{4 mmol NH}_{3}}\\\\= \text{0.0350 mmol Cu(NH$_{3}$)$_{4}$$^{2+}$}$

NH₃ is the limiting reactant, because it forms fewer moles of the complex ion.

(c) Concentration of the complex ion

$\text{The reaction forms 0.0350 mmol Cu(NH$_{3}$)$_{4}$$^{2+}$ in a total volume of 10.00 mL.}\\c = \dfrac{\text{moles}}{\text{litres}} = \dfrac{\text{0.0350 mmol}}{\text{10.00 mL}} = \textbf{0.0035 mol/L}\\\\\text{The concentration of the complex ion is $\large \boxed{\textbf{0.0035 mol/L}}$}$

7 0

3 years ago

Show all work:

Serggg [28]

The equation of the reaction is;

Ca(OH)2(aq) + 2HCl(aq) ------> CaCl2(aq) + 2H2O(l)

<h3>What is neutralization?</h3>

The term neutralization has to do with the process in which an acid reacts with a base to form salt and water only. A neutralization reaction is known by the fact that water is obtained by the reaction of hydrogen and hydroxide ions.

The equation of the reaction is;

Ca(OH)2(aq) + 2HCl(aq) ------> CaCl2(aq) + 2H2O(l)

Learn more about neutralization:brainly.com/question/27891712

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5 0

2 years ago