(1) MO₂(s) + C(s) → M(s) + CO₂ (g), ΔG₁ = 288.9 kJ/mol
(2) C(s) + O₂(g) → CO₂(g), ΔG₂ = -394.4 kJ/mol
By adding both equations 1 + 2 we get the coupled reaction:
MO₂(s) + 2 C(s) + O₂(g) → M(s) + 2 CO₂(g)
ΔG⁰ = ΔG₁ + ΔG₂
= 288.9 + (-394.4) = -105.5 kJ/mol = -105500 J/mol
Temperature T = 25 + 273.15 = 298.15 K
Molar gas constant R = 8.314 J/mol.K
K =
=
= 3.05 x 10¹⁸
Answer:
The chemist can either:
a. Use a small fractionation apparatus.
b. Add a compound with a much higher boiling point.
Explanation:
Using a smaller fractionation apparatus or Vigreux column will help to minimize loss of the distillate.
If a compound with a higher boiling point is added, the vapors of this liquid will displace the vapors of this small amount of compound with a lower boiling point. This compound with a higher boiling point is known as a Chaser.
Answer:
Homogeneous solutions are solutions with uniform composition and properties throughout the solution.
Explanation:
For example a cup of coffee, perfume, cough syrup, a solution of salt or sugar in water, etc. Heterogeneous solutions are solutions with non-uniform composition and properties throughout the solution.
Answer:
If the moles of gas are tripled, the volume must also triple.
Explanation:
According to Avogadro law,
Equal volume of all the gases at same temperature and pressure have equal number of molecules.
The number of moles and volume are directly related to each other. By increasing the number of moles volume also goes to increase with same ratio.
When number of moles decreases the volume also goes to decrease at constant temperature and pressure.
Mathematical expression:
V ∝ n
V = Kn
V/n = k
When volume is changed from V₁ to V₂ by changing the number of moles from n₁ to n₂. Then expression will be,
V₁/n₁ = V₂/n₂
