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BaLLatris [955]
3 years ago
10

How is it possible for two neutral objects to become charged by rubbing them together? A. The binding force of the objects’ atom

s overcomes the frictional force and their atoms become more tightly bound. B. The frictional force overcomes the atoms’ binding force, which releases an electron from the innermost orbit of one of the objects. C. There is no change in the objects. D. The frictional force overcomes the force that binds the electrons to the atoms, enabling the electrons to move elsewhere
Chemistry
1 answer:
FinnZ [79.3K]3 years ago
4 0

Answer:

D. The frictional force overcomes the force that binds the electrons to the atoms, enabling the electrons to move elsewhere

Explanation:

Neutral objects becomes charged by rubbing them together due to the frictional force which overcomes the attractive force holding electrons together in an atom.

Friction is the resistance to flow or movement. When we rub bodies together, the movement of electrons becomes inhibited and this can cause an orbital electron loosely held in an atom to be pulled off as the force of friction increases. This mechanism would result in a body losing electron and another readily gaining that electron as they interact. The loss and gain of electrons causes a neutral body to become charged.

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Please help
photoshop1234 [79]

Answer:

Atomic radius is directly proportional to Metallic reactivity in group 2.

Explanation:

Atomic radius is directly proportional to Metallic reactivity in group 2.

As we move down the group in group 2 which is called as the alkaline earth metals, the atomic number increases due to which the subshell increases. And the outermost shell's electron are less tightly held to the nucleus of the atom. Since the electrons are loosely held that means they can easily participate in reactions and that what makes it reactive down the 2nd group. Therefore alkaline earth metals with higher atomic number are more chemically reactive.

4 0
3 years ago
A chemist prepares a solution of calcium bromide CaBr2 by measuring out 4.81μmol of calcium bromide into a 50.mL volumetric flas
Mariana [72]

Answer:

The concentration of the CaBr2 solution is 96 µmol/L

Explanation:

<u>Step 1:</u> Data given

Moles of Calciumbromide (CaBr2) = 4.81 µmol

Volume of the flask = 50.0 mL = 0.05 L

<u>Step 2:</u> Calculate the concentration of Calciumbromide

Concentration CaBr2 = moles CaBr2 / volume

Concentration CaBr2 = 4.81 µmol / 0.05 L

Concentration CaBr2 = 96.2 µmol /L = 96.2 µM

The concentration of the CaBr2 solution is 96 µmol/L

4 0
3 years ago
A sample of a gas takes up 2.35L of space at room temperature (20.0ºC). What volume will the gas occupy at -5.00ºC? (Hint: Don’t
sergiy2304 [10]
So if it is 2.35L at the temperature 20.0^C and you want the volume at -5.00^C this is hw you would solve it for example 20.0^C to 2.00L it would be 10 degrees per Liter so it would be here 10 degrees every liter so you would do 20.0 % 2.35 = / then find the answer and then find out how many degrees that answer is off of -5.00 then once you get that divide -5.00 with that answer.<span>
  </span>
3 0
3 years ago
What mass of O2 is needed to completely react with 500 g of Fe
Zina [86]

Answer:

solution given:

Explanation:

4Fe +3O2------------>2Fe2O3

4mole. 3mole. 2 mole

224g. 96g. 320g

we have

224 g of fe needed to react completely with 96 g of O2

500g of fe needed to react completely with

96 ×500/224=214.3g of O2

214.3g of O2 is a required answer.

8 0
3 years ago
When floral design first emerged as an art form, which technique was emphasized?
olasank [31]
Using flowers in their natural state and shape
8 0
3 years ago
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