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3 years ago

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which statement about waves is false? a. waves transfer matter b. waves can change direction c. waves can interact with each oth

er d. waves can transfer energy to matter

1 answer:

satela [25.4K]3 years ago

8 0

A.

Waves can transfer energy but they can’t transfer matter

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two forces P and Q pass through a point A which is 4 ft to the right of and 3 ft above a moment center O. force P is 200 lb dire

valentinak56 [21]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

The moment of the resultant of these two forces with respect to O 376 lb-ft CCW which is <span>about moment center point O.</span>

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3 years ago

Oksanka [162]

The spider will cross the driveway <u>25.71 in seconds</u>.

Why?

It's a conversion problem, so, in order to solve it, we need to convert the units of the given information.

Let's convert the given speed (in cm/s) to m/s.

We know that:

$1m=100cm$

So, converting we have:

$14\frac{cm}{s}*\frac{1m}{100cm}=0.14\frac{m}{s}$

Then, calculating the time, we have:

$distance=speed*time\\\\3.6m=0.14\frac{m}{s}*time\\\\time=\frac{3.6m}{0.14\frac{m}{s}}=25.71s$

We have that the spider will cross the driveway in 25.71 seconds.

Have a nice day!

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3 years ago

What does the earths core do

cestrela7 [59]

Answer: Earth scientists have theorized that the Earth's core is responsible for the planet's magnetic field as well as plate tectonics.

Explanation:

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3 years ago

What is the formula for velovity?

GarryVolchara [31]

Answer:

if it's velocity u talking of.....

Explanation:

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3 years ago

a bullet is fired horizontally with a speed of 524 m/s from a height of 22m above the ground. calculate where it will hit the gr

lara31 [8.8K]

Given data:

* The height of the bullet is 22 m.

* The speed of bullet in the horizontal direction is 524 m/s.

Solution:

By the kinematics equation, the time taken by the bullet to reach the ground is,

$h=u_yt+\frac{1}{2}gt^2$

where u_y is the vertical velocity component, t is the time taken to reach the ground, g is the acceleration due to gravity, and h is the height of the bullet,

Substituting the known values,

$\begin{gathered} 22=0+\frac{1}{2}\times9.8\times t^2 \\ t^2=\frac{22\times2}{9.8} \\ t^2=4.49 \\ t=2.12\text{ s} \end{gathered}$

Thus, the time taken by the bullet to reach the ground is 2.12 seconds.

By the kinematics equation for the horizontal motion, the horizontal range of the bullet is,

$R=u_xt+\frac{1}{2}at^2$

where u_x is the horizontal component of the velocity, a is the acceleration along the horizontal direction, t is the time taken to reach the ground and R is the horizontal range,

Substituting the known values,

$\begin{gathered} R=524\times2.12+0 \\ R=1110.9\text{ m} \end{gathered}$

Thus, the horizontal range of the bullet is 1110.9 meters.

Hence, the bullet hit the ground at 1110.9 meters.

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1 year ago