The question incomplete , the complete question is:
A student dissolves of 18.0 g urea in 200.0 mL of a solvent with a density of 0.95 g/mL . The student notices that the volume of the solvent does not change when the urea dissolves in it. Calculate the molarity and molality of the student's solution. Round both of your answers to significant digits.
Answer:
The molarity and molality of the student's solution is 1.50 Molar and 1.58 molal.
Explanation:
Moles of urea = 
Volume of the solution = 200.0 mL = 0.2 L (1 mL = 0.001 L)

Molarity of the urea solution ;

Mass of solvent = m
Volume of solvent = V = 200.0 mL
Density of the urea = d = 0.95 g/mL


(1 g = 0.001 kg)
Molality of the urea solution ;


The molarity and molality of the student's solution is 1.50 Molar and 1.58 molal.
Answer:
Explanation:(differences)SOLIDS have maximum intermolecular attraction and fixed shape so their particles are stable. LIQUIDS have small particles and are tightly held by molecular bond but not as tight as solid. liquid assume the shape of their container.GAS has free movement of particles...SIMILARITIES.. Liquid,solid and gases can be kept in containers...
Answer:
light with a high enough intensity
Explanation:
Answer:
To monitor Pressure increase
Explanation:
the more pressure, the higher the production of the gas, which can be recorded, more pressure meaning higher production. Then vary the temperature.