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3 years ago

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An electron is released from rest in a vacuum between two flat, parallel metal plates that are apart and are maintained at a con

stant electric potential difference of Volts. If the electron is released at the negative plate, what is its speed just before it strikes the positive plate?

1 answer:

il63 [147K]3 years ago

4 0

Answer:

v = √(2qV/m)

Explanation:

½mv² = qV

mv² = 2qV

v² = 2qV/m

v = √(2qV/m)

where v = drift velocity

q = charge

V = p.d

m = mass of the electron

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Some car manufacturers claim that their vehicles could climb a slope of 42 ∘. For this to be possible, what must be the minimum

Paladinen [302]

Answer:

D. 0.9

Explanation:

Calculating minimum coefficient of static friction, we first resolve the forces (normal and frictional) acting on the vehicle at an angle to the horizontal into their x and y components. After this, we can now substitute the values of x and y components into equation of static friction. Diagrammatic illustration is attached.

Resolving into x component:

∑ $F_{x} = F_{s} - mgsin\alpha =0$

$F_{s} = mgsin\alpha$ ------(1)

Resolving into y component:

∑ $F_{y} = F_{n} - mgcos\alpha =0$

$F_{n} = mgcos\alpha$ ------(2)

Static frictional force, $F_{s} \leq$ μ $F_{n}$ ------(3)

substituting $F_{s}$ from equation (1) and $F_{n}$ from equation (2) into equation (3)

$mgsin\alpha \leq$ μ $mgcos\alpha$

$sin\alpha \leq$ μ $cos\alpha$

μ $\geq \frac {sin\alpha}{cos\alpha}$

μ $\geq tan\alpha$

The angle the vehicles make with the horizontal α = 42°

μ ≥ tan 42°

μ ≥ 0.9

6 0

3 years ago

Select the correct answer.

Natali5045456 [20]

(NH4)2CO3(s) ⇄ 2NH3(g) + CO2(g) + H2O (g)

The effect that adding water (H2O) have in reaction above is that The concentration of the product would decrease, and the concentration of reactant would increase. (answer C)

<u><em>Explanation</em></u>

If the concentration of one substance is changed, the equilibrium shift to minimize the effect of that change.

H2O in reaction above is a product.

Increase of water (H2O) concentration will led to the shift of equilibrium to the left ( reactant side) .The concentration of reactant increase as that of product decrease.

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3 years ago

Which of the following statements about Ohm's Law is true? A. Increasing the voltage decreases current. B. Keeping the same volt

Luden [163]

The correct answer is option D

The Ohm's Law states that current passing through a conductor is directly proportional to the voltage across the conductor.

Current =voltage/ resistance

The resistance causes hindrance in the path of the current and does not allows it to flow so, we must reduce the resistance to increase the flow of current in the conducting wire.

6 0

3 years ago

Read 2 more answers

What mass of a material with density rho is required to make a hollow spherical shell having inner radius r1 and outer radius r2

Margarita [4]

Answer:

$m=\rho\times \frac{4}{3} \times \pi \times(r_2^3-r_1^3 )$

Explanation:

We have to make a hollow sphere of inner radius $r_1$ and outer radius $r_2$ .

Then the mass of the material required to make such a sphere would be calculated as:

Total volume of the spherical shell:

$V_t=\frac{4}{3} \pi.r_2^3$

And the volume of the hollow space in the sphere:

$V_h=\frac{4}{3} \pi.r_1^3$

Therefore the net volume of material required to make the sphere:

$V=V_t-V_h$

$V=\frac{4}{3} \pi(r_2^3-r_1^3)$

Now let the density of the of the material be $\rho$ .

<u>Then the mass of the material used is:</u>

$m=\rho.V$

$m=\rho\times \frac{4}{3} \times \pi \times(r_2^3-r_1^3 )$

4 0

4 years ago

If the velocity of a car is 45 km/h west how far can it travel in 0.5 hours?

marissa [1.9K]

Answer: 22.5 km

Explanation: Solution:

v=d/t

Derive to find d

d= vt

= 45 km/h x 0.5 h

= 22.5 km

Cancel hours and the remaining unit is in km.

6 0

3 years ago