Considering<br> will Fever equal zero?<br> O yes<br> О по<br> O not enough information

a jetliner goes from rest to a takeoff speed of 162 mi/h in 39.5 s. what is the magnitude of its average acceleration?

irakobra [83]

Acceleration = V/t

First set velocity to m/s

V = 72.42 m/s

Now we divide velocity by time

A = 72.42/39.5
A = 1.83 m/s^2

3 0

3 years ago

you slide abox of books at constant speed up a30 degree ramp, applying a force of 200 newtons directed up the slope. The coeffic

Tomtit [17]

The work done is 400 J

Explanation:

The work done by you in pushing the box along the slope is given by

$W=Fd$

where

F is the magnitude of the force applied

d is the distance covered by the box along the slope

Here we have the following:

F = 200 N is the magnitude of the force applied

$d=\frac{h}{sin \theta}$ is the distance covered, where

h = 1 m is the vertical rise

$\theta=30^{\circ}$ is the slope of the plane

Substituting and solving, we find

$W=F\frac{h}{sin \theta}=\frac{(200)(1)}{sin 30^{\circ}}=400 J$

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

5 0

3 years ago

5. Three children are at work. One is pushing a chair, another is pushing the sofa and the third one is pushing an empty trolley

katen-ka-za [31]

Answer:

sofa

Explanation:

because the sofa is heavy and the amount of friction is high due to the amount of opposite friction is pushing it back

4 0

3 years ago

Find the ratio of the final speed of the electron to the final speed of the hydrogen ion, assuming non-relativistic speeds. Take

KiRa [710]

Answer:

$\frac{V_{e}}{V_{h}}=0.428*10^{2}$

Explanation:

From conservation of energy states that

$K_{i}+v_{i}=v_{f}+K_{f}\\ as\\K_{i}=0\\K_{f}=1/2mv^{2}\\ v_{i}=qv\\v_{f}=0\\So\\qv=1/2mv^{2}\\ v=\sqrt{\frac{2qv}{m} }\\ Velocity_{electron}=\sqrt{\frac{2qv}{m_{e}} }\\Velocity_{hydrogen}=\sqrt{\frac{2qv}{m_{h}} }\\\frac{V_{e}}{V_{h}}=\sqrt{\frac{\frac{2qv}{m_{e}}}{\frac{2qv}{m_{h}}}}\\\frac{V_{e}}{V_{h}}=\sqrt{\frac{m_{h}}{m_{e}} }\\\frac{V_{e}}{V_{h}}=\sqrt{\frac{1.67*10^{-27} }{9.11*10^{-31} } }\\\frac{V_{e}}{V_{h}}=0.428*10^{2}$

5 0

3 years ago

Does anyone know how to do this?

SIZIF [17.4K]

Explanation:

By Hooke's Law,

F=kx

The only force acting here is weight, and x is the extension of the string (you need to convert this to mm) so

mg=kx

(0.15)(9.81)=k ((420-300)x10^-3)

Then just solve this equation.

8 0

3 years ago

Considering will Fever equal zero? O yes О по O not enough information