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Alex777 [14]
3 years ago
6

I'm a bit confused

Physics
1 answer:
DochEvi [55]3 years ago
8 0
When an object is thrown upwards, it reaches a maximum height and then comes back to its starting position. If we put f(t) = 0, we can get the time the ball was thrown and the time it returned.
Solving:
-16t² + 94t + 12 = 0
t = -0.125 and t = 6; negative time is not possible so the first solution is discarded.
The maximum height lies at the time exactly between the two times of zero displacement. Max height at
t = (-0.125 + 6)/2 = 2.9375 s ≈ 3
3 < t < 6
Therefore, the answer is the first option.
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