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MrRa [10]
3 years ago
8

Which of the following compounds has the highest oxygen content by weight?

Chemistry
2 answers:
slega [8]3 years ago
6 0

The molecular weight is 18, and 16 of that is oxygen.  

So, water is 16/18 * 100 = 88.9% oxygen by weight.  

None of the other compounds have as high an oxygen content (by weight) as water.  

This is a trick question, and the University Chemistry grad fell for it.  

If you have the same weight of each compound (let's say, 10 grams, for example), then H2O has the most oxygen weight (8.89 g).

mixer [17]3 years ago
6 0

Answer:

This question is incomplete. The completed question is below

Which of the following compounds has the highest oxygen content, by weight? a. NaO b. CO c. BaO  d. H₂O

The correct option is d. H₂O

Explanation:

<u>The percentage of oxygen by weight in NaO</u> is

atomic mass of sodium (Na) is 23 g/mol while that of oxygen is 16 g/mol

molar mass of NaO = 23 + 16 = 39g

% by mass of oxygen  = 16/39 × 100 = <em>41.03 %</em>

<u>The percentage of oxygen by weight in CO</u> is

atomic mass of carbon (C) is 12 g/mol while that of oxygen is 16 g/mol

molar mass of CO = 12 + 16 = 28g

% by mass of oxygen = 16/28 × 100 = <em>57.14 %</em>

<u>The percentage of oxygen by weight in BaO</u> is

atomic mass of barium (Ba) is 137 g/mol while that of oxygen is 16 g/mol

molar mass of BaO = 137 + 16 = 153g

% by mass of oxygen = 16/153 × 100 = <em>10.46 %</em>

<u>The percentage of oxygen by weight in H₂O</u> is

atomic mass of Hydrogen (H) is 1 g/mol while that of oxygen is 16 g/mol

 molar mass of H₂O = (2 × 1) + 16 = 18g

% by mass of oxygen = 16/18 × 100 = 88.89 %

From the above calculations, it can be deduced that H₂O has the highest oxygen content by weight

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The electron group arrangement of PH₃ is tetrahedral. The molecular shape is a Trigonal pyramid, and the bond angle is 93°.

<h3>What is the bond angle?</h3>

The angle between the atoms in a compound is known as the bond angle. The degree of the binding angle is specified. There is also the bond length. It is the separation between the two atoms' nuclei.

The bond angle between the atoms of phosphine is 93°. It has one lone pair. The central atom is covered with 4 atoms.

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The balanced equation for the ionization of the weak base pyridine,C5H5N in water, H2O

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<h3>What is the balanced equation for the ionization?</h3>

Generally, Pyridine is characterized by a ring structure, in this characteristic ring structure N is sp2 hybridized, hence creating a lone pair present on N so s - character is more, as well as lone pair, is present.

Therefore, Considering The following functions of the equation:weak base pyridine,C5H5N in water, H2O

We write the balanced equation for the ionization as

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In order for a process to be spontaneous, Multiple Choice the entropy of the surroundings must increase. the entropy of the surr
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Answer:

The correct answer is entropy change of the surrounding plus the entropy change of the system must be positive.

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8 0
3 years ago
Calculate the concentrations of all species present in a 0.26 M solution of ethylammonium chloride (C2H5NH3Cl).
Alina [70]

Answer:

0.00000223

Explanation:

pKa for C2H5NH3+ = 10.7

pKw = 14.0

pKa + pKb = pKw

10.7 + pKb = 14.0

pKb = 14.0 - 10.7

pKb = 3.30

C2H5NH3Cl is a salt of ethylamine and HCl so it will dissolve in water to produce  C2H5NH3^+ + Cl^-

The base hydrolysis reaction:  C2H5NH3^+(aq) + H2O(l) <=> C2H5NH2(aq) + H3O^+(aq)

This reaction is described by Kb.

Kb = [C2H5NH2][H3O^+]/[C2H5NH3^+]

Let [C2H5NH2] = [H3O^+] = x,

so [C2H5NH3^+] = 0.26 - x

Kb = x^2/(0.26 - x) = 2.00 x 10^-11  

Let's solve for x. In this equation,  It is possible to solve without the use quadratic equation. So we can assume that 0.26 - x  is approximately equal to 0.26.  We won't know until we do the calculation.

We get:  x^2 + 2.00 x 10^-11x - 4.99 x 10^-12 = 0

With the use of a quadratic calculator.

x = 2.23 x 10^-6 M = [C2H5NH2] = [H3O^+]

0.26 - x  is just 0.26 M in this problem because 2.23 x 10^-6 M is insignificant.

[C2H5NH3^+] = 0.26 M = [Cl^-]

NOTE:

pH = -log [H3O^+] = -log(2.23 x 10^-6) = 5.65

Ka is the acid dissociation constant

Kb is the base dissociation constant

5 0
3 years ago
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