"Indoor environments are much less polluted than outdoor <span>environments" is the best option since indoor environments often rely on separate air and ventilation systems. </span>
Answer:
mechanical weathering breaks rocks into smaller forms without any change in their composition whereas chemical weathering breaks down rocks by forming new minerals .
or simply mechanical weathering is the physical breakdown of rocks while chemical weathering is the breakdown of rocks through chemical reactions .
Answer:
The soil has a percentage of water by mass of 27.8 %.
Explanation:
Keeping in mind that
- Mass of Clay = Mass of water + Mass of Dry Soil
we can <u>calculate the mass of water</u>:
- 1350 g = Mass of Water + 975 g
We can then <u>calculate the mass percentage of water in the soil</u>:
- 375 / 1350 * 100% = 27.8 %
Yo sup??
number of protons=number of electrons =8
but this is the condition when the molecule is neutral
since it has a +3 charge now therefore no of electron is
=8-3
=5
The correct answer is option B
Hope this helps
<span>Data:
1) molar
mass: 58.0714 g.
2) mass analysis
C: 18 g
H: 3 g
O: 8 g.
Solution
</span>
<span>What is the percent composition of all the components in the liquid?
mass of C + mass of H + mass of O = 18g + 3g + 8g = 29 g
Percent composition:
C: (18g / 29g) * 100 = 62%
H: (3g / 29g) * 100 = 10%
O: (8g / 29g) * 100 = 28%
--------------
Total 100%
What is the empirical formula of the compound?
Convert masses to number of moles by dividing each mass by the atomic mass of the correspondant element:
C: 18 g/ 12.0 g/mol = 1.5 mol
H: 3 g / 1.0 g/mol = 3 mol
O: 8 g / 16 g/mol = 0.5 mol
Divide each number of moles by the smaller, i.e. 0.5 mol
=> C: 1.5 mol / 0.5 mol = 3 mol
=> H: 3 mol / 0.5 mol = 6 mol
=> O: 0.5 mol / o.5 mol = 1 mol
=> Empirical formula: C3 H6 O
What is the molecular formula of the unknown liquid?
First,calculate the molar mass of the empirical formula:
C3 H6 O => 3 * 12 g/mol + 6*1 g/mol + 16 g/mol = 58 g/ mol
Secont, given that the molar mass is the same that the empirical mass, the molecular formula is the same empirical formula.
=> Molecular formula = C3 H6 O.
This compound has been
identified as a ketone.
Go online and figure out the name of this
compound.
It is easy to find that this compound is propanone or acetone (both names are valid).
Now you can go online and find its characteristics and common uses.
Can you identify
the killer from this information? How?
Likely they think you can presume that the killer is the actress, because women use acetone regularlty to remove the nail polish.
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