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3 years ago

11

A long point-object, mass = 1.0 kg, moves in a circular path at a radial distance = 0.5 m from the axis of rotation. What is the

moment of inertia of the point mass? Give your answer 3 significant figures.

1 answer:

Vinvika [58]3 years ago

5 0

Answer: $0.25\ kg-m^2$

Explanation:

Given

mass of Point object $m=1 kg$

Distance $r=0.5 m$

Since mass is moving in circular path therefore every time mass is at distance of r from center .

Also Moment of Inertia tells about the distribution of mass over the given region with respect to center of mass.

Therefore $I=mr^2$

$I=1\times 0.5^2$

$I=0.25\ kg-m^2$

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4 years ago

An umbrella tends to move upward on a windy day because _____.

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3 years ago

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3 years ago

If the sprinter accelerates at that rate for a distance of 15 m, and then maintains the velocity he has at that point for the re

ahrayia [7]

Answer:

The time for the entire race is 11.39 sec.

Explanation:

Given that,

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Remainder distance = 100 m

Suppose A sprinter begins a race with an acceleration of 3.4 m/s².

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$s=ut+\dfrac{1}{2}at^2$

Put the value in the equation

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Put the value into the formula

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The sprinter need to covers only 85 m.

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Using formula of time

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Put the value into the formula

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Put the value into the formula

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$t''=11.39\ sec$

Hence, The time for the entire race is 11.39 sec.

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3 years ago