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suter [353]
3 years ago
9

5. Identifying the limiting reagent: Given the reaction 2Cu + S → Cu2S, if you had 3 moles of both Cu and S, which would you run

out of first?
Chemistry
1 answer:
Lady_Fox [76]3 years ago
8 0

The reaction is

2Cu + S → Cu2S

So as per balanced given reaction we need one mole of sulphur over two moles of copper

Or

To react with one mole of sulphur we need two moles of copper

Thus we can say that the mole ration required for complete reaction will be

Cu : S = 2 : 1

As per the given problem the moles of each Cu and S are 3 moles

Thus for each three moles of given sulphur we need six moles of Cu to give three moles of Cu2S

However we have only three moles of copper available

So the limiting reagent is copper

It is going to decide the actual yield of reaction

The three moles of Copper will get completely utilized and only 1.5 moles of S will be used in the reaction making S an excess reagent

The moles of S left will be = 1.5 moles

moles of Cu2S formed = 1.5 moles


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In this case, for this heat transfer process in which the heat lost by the hot platinum is gained by the cold deuterium oxide based on the equation:

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m_{Pt}=\frac{-m_{Deu}Cp_{Deu}(T_f-T_{Deu})}{Cp_{Pt}(T_f-T_{Pt})} \\\\m_{Pt}=\frac{-1.00L*1110g/L*4.211J/(g\°C)*(41.9-25.5)\°C}{0.1256J/(g\°C)*(41.9-200.0)\°C} \\\\m_{Pt}=3860.4g

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V_{Pt}=\frac{3860.4g}{21.45g/cm^3}\\ \\V_{Pt}=180cm^3

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