Answer:
1. Richter
2. moment
Explanation:
I just submitted it on edge! Try it out for yourself bc I promise this is 100 percent correct! Have a great day
Convert Mg to grams
1g =1000mg what about 3.91 Mg
= 3.91mg x 1g/1000mg= 3.91 x10^-3 g
moles= mass/molar mass
that is 3.91 x10^-3g /99 g/mol=3.95 x10^-5moles
concentration= moles / vol in liters
that is 3.95 x10^-5/100 x1000= 3.94 x10^-4M
equation for dissociation of CUCl= CUCl----> CU^+ +Cl^-
Ksp=(CU+)(CI-)
that is (3.95 x10^-4)(3.95 x10^-4)
Ksp= 1.56 x10^-7
To solve the question you use the following formula:
concentration (1) × volume (1) = concentration (1) × volume (1)
3 M × volume (1) = 1.8 M × 50 mL
volume (1) = (1.8 M × 50 mL) / 3 M = 30 mL
<h2>
Answer:</h2>
Both of them will have same kinetic energy.
<h2>
Explanation:</h2>
- Kinetic energy is the energy of motion, every object in motion posses some kinetic energy.
- Kinetic energy can be calculated by the given formula,
i.e, K.E = 1/2 mv² .
Where, K.E is kinetic energy,
m is mass of the object
v is the velocity of the object
- On observing the formula we can state that K.E is directly proportional to mass(m) and velocity(v) of the object.
- Obviously, birds have more mass than bees but in question it has given 10 Kg of bees and 10 Kg of birds which means mass is same and also both of them are travelling with same velocity i.e 10m/s and hence both of them will have same kinetic energy(as both of the variables i.e m and v are same).
Result: Both bees and birds have same kinetic energy.
Answer:
C8H17N
Explanation:
Mass of the unknown compound = 5.024 mg
Mass of CO2 = 13.90 mg
Mass of H2O = 6.048 mg
Next, we shall determine the mass of carbon, hydrogen and nitrogen present in the compound. This is illustrated below:
For carbon, C:
Molar mass of CO2 = 12 + (2x16) = 44g/mol
Mass of C = 12/44 x 13.90 = 3.791 mg
For hydrogen, H:
Molar mass of H2O = (2x1) + 16 = 18g/mol
Mass of H = 2/18 x 6.048 = 0.672 mg
For nitrogen, N:
Mass N = mass of unknown – (mass of C + mass of H)
Mass of N = 5.024 – (3.791 + 0.672)
Mass of N = 0.561 mg
Now, we can obtain the empirical formula for the compound as follow:
C = 3.791 mg
H = 0.672 mg
N = 0.561 mg
Divide each by their molar mass
C = 3.791 / 12 = 0.316
H = 0.672 / 1 = 0.672
N = 0.561 / 14 = 0.040
Divide by the smallest
C = 0.316 / 0.04 = 8
H = 0.672 / 0.04 = 17
N = 0.040 / 0.04 = 1
Therefore, the empirical formula for the compound is C8H17N
