Let:
Vx = the pulling component of force
Vy = the lifting component of force
Vy:
Sin(n°) = Vy/hypotenuse
hypotenuse * Sin(n°) = Vy
100N*sin(30°) = Vy
50N = Vy
Vx:
Cos(n°) = Vx/hypotenuse
Hypotenuse * cos(n°) = Vx
100N*cos(30°) =Vx
about 86.6N = Vx
So to solve for this problem, this is computed by the
following steps:
Vp / Vs ( = Np / Ns
Where:
Vp = Voltage Primary
Vs = Voltage Secondary
Np = Turn ratio Primary
Ns = Turn ratio Secondary.
So plugging in our values: <span>
110 / 4.9 = N</span>p / Ns<span>
N</span>p / Ns =22.44, so <span>the answer is 22 coils.</span>
Answer:
1.7 BTU
Explanation:
q = mCΔT
q = (25 g) (0.9 J/g/°C) (100°C − 20°C)
q = 1800 J
q = 1800 J × (1 BTU / 1055 J)
q = 1.7 BTU
Here, pressure is constant, so volume will be directly proportional to the temperature according to Charles law.
So, V₁/T₁ = V₂/T₂
V₂ = 0.20 * 533 / 333
V₂ = 0.32 m³
In short, Your Answer would be: 0.32 m³
Hope this helps!
