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Radda [10]
2 years ago
7

Question #2: Where does hope come from? Just you? The people around you? Explain.

Physics
1 answer:
Tanya [424]2 years ago
8 0

Answer:

it depends ether people can give you hope or you can have hope

Explanation:

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What kind of system is generally composed of a fluid system to move the heat from the collector to its point of usage and a rese
Mkey [24]

Solar heating is the system composed of a fluid system to move the heat from the collector to its point of usage and a reservoir to stock the heat

<u>Explanation:</u>

The options given here like coal burning uses solid material as the source to heat and to generate energy. Similarly, nuclear power also requires solid particles like atoms or neutrons to strike the moderators forming energy.

In both of these cases, fluid system is present but it is used completely as coolant and to maintain the temperature. Thus, the remaining system that is solar heating has been done for water tanks where the fluid as water is used to move the heat from its collector to its point of usage. Even in solar system it is used as reservoir to stock the heat.

5 0
3 years ago
In nuclear fission the nucleus is divided into two or more fragments, releasing Question 8 options: protons and energy. neutrons
Dmitrij [34]

Answer:

the answer is neutrons and energy

8 0
2 years ago
A 1.0-kg block moving to the right at speed 3.0 m/s collides with an identical block also moving to the right at a speed 1.0 m/s
____ [38]

Answer:

Speed of both blocks after collision is 2 m/s

Explanation:

It is given that,

Mass of both blocks, m₁ = m₂ = 1 kg

Velocity of first block, u₁ = 3 m/s

Velocity of other block, u₂ = 1 m/s

Since, both blocks stick after collision. So, it is a case of inelastic collision. The momentum remains conserved while the kinetic energy energy gets reduced after the collision. Let v is the common velocity of both blocks. Using the conservation of momentum as :

m_1u_1+m_2u_2=(m_1+m_2)v

v=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}

v=\dfrac{1\ kg\times 3\ m/s+1\ kg\times 1\ m/s}{2\ kg}

v = 2 m/s

Hence, their speed after collision is 2 m/s.

7 0
3 years ago
A car is brought to rest in a distance of 484m using a constant acceleration of -8.0m/s^2. What was the velocity of the car when
Agata [3.3K]

Answer:

88 m/s

Explanation:

To solve the problem, we can use the following SUVAT equation:

v^2-u^2=2ad

where

v is the final velocity

u is the initial velocity

a is the acceleration

d is the distance covered

For the car in this problem, we have

d = 484 m is the stopping distance

v = 0 is the final velocity

a=-8.0 m/s^2 is the acceleration

Solving for u, we find the initial velocity:

u=\sqrt{v^2-2ad}=\sqrt{-2(8.0)(484)}=88 m/s

6 0
3 years ago
Which diagram best represents the electric field around a negatively charged conducting sphere? (See pic)
dalvyx [7]
The answer is D !!!!!!!
3 0
3 years ago
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