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3 years ago

How many atoms are in 36.1 g of boron

Chemistry

1 answer:

Katen [24]3 years ago

8 0

Answer:

The answer is 2.011 *10^24

Explanation:

Looking for atoms in boron,

Molar mass of B = 10.81g/mol

There is 36.1g of B,.

Using avogadro constant = 6.023* 10^23

36.1g of B= 6.023 *10^23/10.81 * 36.1g

That is, 6.023*10^23 divided by 10.81 multiplied by 36.1g

From this calculation, we get

36.1g of boron = 2.011 * 10^24atoms.

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Hitman42 [59]

Answer:

An ice pack uses friction and the chemicals inside make it mix to make it cold

Explanation:

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3 years ago

Given that sodium chloride is 39.0% sodium by mass, how many grams of sodium chloride are needed to have 100.mg of Na present? G

seraphim [82]

Answer: The mass of sodium chloride solution present is 0.256 grams.

Explanation:

We are given:

39.0 % of sodium in sodium chloride solution

This means that 39.0 grams of sodium is present in 100 grams of sodium chloride solution

Mass of sodium given = 100 mg = 0.1 g (Conversion factor: 1 g = 1000 mg)

Applying unitary method:

If 39 grams of sodium metal is present in 100 grams of sodium chloride solution

So, if 0.1 grams of sodium metal will be present in = $\frac{100}{39}\times 0.1=0.256g$ of sodium chloride solution.

Hence, the mass of sodium chloride solution present is 0.256 grams.

8 0

3 years ago

10. If 3.5 kJ of energy are added to a 28.2 g sample of iron at 20°C, what

igor_vitrenko [27]

Answer:

569K

Explanation:

Q = 3.5kJ = 3500J

mass = 28.2g

∅1 = 20°C = 20 + 273 = 293K

∅2 = x

c = 0.449

Q = mc∆∅

3500 = 28.2×0.449×∆∅

3500 = 12.6618×∆∅

∆∅ = 3500/12.6618

∆∅ = 276.4220

∅2 - ∅1 = 276.4220

∅2 = 276.4220 + ∅1

∅2 = 276.4220 + 293

∅2 = 569.4220K

∅2 = 569K

3 0

2 years ago

C9H20 + 02 - > CO2 + H2O what is the balanced equation of this

san4es73 [151]

Hey there!

C₉H₂O + O₂ → CO₂ + H₂O

First let's balance the C.

There's 9 on the left and 1 on the right. So, let's add a coefficient of 9 in front of CO₂.

C₉H₂O + O₂ → 9CO₂ + H₂O

Next let's balance the H.

There's 2 on the left and 2 on the right. This means it's already balanced.

C₉H₂O + O₂ → 9CO₂ + H₂O

Lastly, let's balance the O.

There's 3 on the left and 19 on the right. So, let's add a coefficient of 9 in front of O₂.

C₉H₂O + 9O₂ → 9CO₂ + H₂O

This is our final balanced equation.

Hope this helps!

8 0

3 years ago

Make the equation equal Fe(NO3)3+KSCN —> Fe(SCN)3 + K(NO3)3

Advocard [28]

Answer:

Fe(NO₃)₃ + 3KSCN → Fe(SCN)₃ + 3KNO₃

Explanation:

Chemical equation:

Fe(NO₃)₃ + KSCN → Fe(SCN)₃ + KNO₃

Balanced Chemical equation:

Fe(NO₃)₃ + 3KSCN → Fe(SCN)₃ + 3KNO₃

Type of reaction:

It is double displacement reaction.

In this reaction the anion or cation of both reactants exchange with each other. In given reaction the cation Fe⁺³ exchange with cation K⁺.

The given reaction equation is balanced so there are equal number of atoms of each elements are present on both side of equation and completely hold the law of conservation of mass.

Double replacement:

It is the reaction in which two compound exchange their ions and form new compounds.

AB + CD → AC +BD

5 0

3 years ago