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irinina [24]
3 years ago
7

How many atoms are in 36.1 g of boron

Chemistry
1 answer:
Katen [24]3 years ago
8 0

Answer:

The answer is 2.011 *10^24

Explanation:

Looking for atoms in boron,

Molar mass of B = 10.81g/mol

There is 36.1g of B,.

Using avogadro constant = 6.023* 10^23

36.1g of B= 6.023 *10^23/10.81 * 36.1g

That is, 6.023*10^23 divided by 10.81 multiplied by 36.1g

From this calculation, we get

36.1g of boron = 2.011 * 10^24atoms.

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Usimov [2.4K]

Answer:

<em>Most fire extinguishers work by separating the fuel from the oxygen. The oxygen comes from the air. It is the same oxygen we breathe. Since the oxygen has to be in contact with the fuel, if you can coat the fuel with something that keeps the oxygen away, the fire will go </em><em>out.</em><em> </em><em>S</em><em>ome </em><em>ways </em><em>of </em><em>using </em><em>fire </em><em>extinguisher </em><em>are:</em>

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Explanation:

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2 years ago
Balance the following equations:
Brilliant_brown [7]

Answer:

1) 0 C2H4O2 + 0 O2 -> 0 CO2 + 0 H2O (balanced)

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LHS (Left hand side)

V: 2

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Ca: 1

S: 1 x 5 [to balance with the right hand side of the equation]

RHS (Right hand side)

V: 2

O: 1 x 5 [to balance with the left hand side of the equation]

Ca: 1

S: 5

When you balance any elements, you have to balance the whole chemical compound.

Thus,

V2O5 + <em><u>5</u></em> CaS -> <em><u>5</u> CaO</em> + V2S5

LHS CHECK:

V: 2

O: 5

Ca: 5

S: 5

RHS CHECK:

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O: 5

Ca: 5

S: 5

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LHS:

S: 8

O: 2

RHS:

S: 1 x 8 [to balance with LHS]

O: 2

When you balance any elements, you have to balance the whole chemical compound.

S8 + O2 -> <em><u>8</u></em><em><u> </u></em>SO2

When we add 8 to the RHS, it gives us 8S, 16 O.

In order to balance that into the RHS, I need to multiply the O2 by 8, which will give 8(O2) = 16 O particles.

Therefore, <em><u>S8</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em><em><u>8</u></em><em><u> </u></em><em><u>O2</u></em><em><u> </u></em><em><u>-</u></em><em><u>></u></em><em><u> </u></em><em><u>8</u></em><em><u> </u></em><em><u>SO2</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>final</u></em><em><u> </u></em><em><u>answer</u></em><em><u> </u></em><em><u>for</u></em><em><u> </u></em><em><u>(</u></em><em><u>3</u></em><em><u>)</u></em><em><u>.</u></em>

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