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2 years ago

1. Cam Newton can sprint 40 meters in 5.79 seconds! How fast can he run?

Physics

2 answers:

Sever21 [200]2 years ago

7 0

Answer:

thats cap cause we all know tht cam newton is the best qb ever and hes the fastest the strongest dude in the world the best qb THE BEST he is the best i hope this answerd ur question

Explanation:

Vesnalui [34]2 years ago

3 0

This is a Physics question where we need to figure out how many meters Cam can run per second. To figure this out we divide the distance by the change in time.

40/5.79 = 6.9 meters per second approximately.

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The aorta pumps blood out of the heart to the rest of the body. Please select the best answer from the choices provided. T or f

Daniel [21]

The left ventricle relaxes and fills up with blood before squeezing and pumping the oxygen-rich blood through the aortic valve into the aorta — the main artery that carries blood to your body.<u>TRUE</u>

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3 years ago

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onsider 1000 mL of a 1.00 × 10-4 M solution of a certain acid HA that has a Ka value equal to 1.00 × 10-4. Water was added or re

solmaris [256]

Answer:

The volume of the final solution, V = 0.0305L

Explanation:

Number of moles = Concentration * volume

Concentration of HA = 1.00 * 10⁻⁴M

Volume of HA = 1000mL = 1 L

Number of moles of HA = 1.00 * 10⁻⁴ * 1

Number of moles of HA = 1.00 * 10⁻⁴ mols

Equation of reaction:

HA → H⁺ + A⁻

If 1 mol of HA produces 1 mol of H⁺ and A⁻, 1.00 * 10⁻⁴ mol of HA will produce 1.00 * 10⁻⁴ mol of H⁺ and A⁻.

Since only 16% dissociation occurs = 0.16

Number of moles of H⁺ produced = 0.16 * 1.00 * 10⁻⁴

Number of moles of H⁺ produced = 1.6 * 10⁻⁵mols

Number of moles of A⁻ produced = 0.16 * 1.00 * 10⁻⁴

Number of moles of A⁻ produced = 1.6 * 10⁻⁵mols

Since 16% of HA dissociated into H⁺ and A⁻, 84% of HA is left

Number of mols of HA left = 0.84 * 1.00 * 10⁻⁴

Number of mols of HA left = 8.4 * 10⁻⁵mols

Concentration = num of moles/volume

Let the volume of the final solution be V

Conc of HA = 8.4 * 10⁻⁵/V

Conc of H⁺ = 1.6 * 10⁻⁵/V

Conc of A⁻ = 1.6 * 10⁻⁵/V

To calculate the dissociation constant

$k_{a} = [H^{+} ][A^{-} ]/[HA]$

$k_{a}= [1.6 * 10^{-5} /V][1.6 * 10^{-5} /V]/[8.4 * 10^{-5} /V]\\k_{a}= 3.05 * 10^{-6} /V\\k_{a} = 1.00 * 10^{-4}\\ 1.00 * 10^{-4} = 3.05 * 10^{-6} /V\\V= 3.05 * 10^{-6}/ 1.00 * 10^{-4}\\V=3.05 * 10^{-2}\\V=0.0305 L$

3 0

2 years ago

A 107 gram apple falls from a branch that is 2 meters above the ground. (a) How much time elapses before the apple hits the grou

andreev551 [17]

Answer:

The time of motion is 0.64 s.

Explanation:

Given;

mass of the apple, m = 107 g

height of fall, h = 2 m

The velocity of the apple when it hits the ground is calculated from the law of conservation of energy;

$P.E = K.E\\\\mgh = \frac{1}{2} mv^2\\\\gh = \frac{1}{2} v^2\\\\v^2 = 2gh\\\\v = \sqrt{2gh} \\\\v = \sqrt{2\times 9.8\times 2} \\\\v = 6.261 \ m / s$

The time of motion is calculated;

v = u + gt

6.261 = 0 + 9.8t

6.261 = 9.8t

t = 6.261 / 9.8

t = 0.64 s

Therefore, the time of motion is 0.64 s

7 0

2 years ago

Starting from rest, a particle moving in a straight line has an acceleration of a = (2t - 6) m/s^2, where t is in seconds. What

hjlf

To solve this problem we will use the given expression and derive it in order to find the algebraic expressions of velocity and position. These equations will be similar to those already known in the cinematic movement but will be subject to the previously given function. We start deriving the equation for velocity

$a = 2t-6$

$\frac{dv}{dt} = 2t-6$

Integrate acceleration equation

$\int dv = (2t-6)dt$

$v = 2(\frac{t^2}{2})-6t+C_1$

$v=t^2-6t+C_1$

At $t = 0, v = 0$

Replacing,

$0 = 0^2-6*0+C_1$

Therefore the value of the first Constant is

$C_1 = 0$

The expression can be escribed as,

$v = t^2-6t$

Calculate the velocity after 6s,

$v=t^2-6t$

$v = 6^2-6*6$

$v = 0m/s$

Now using the same expression we can derive the equation for distance

$v = t^2-6t$

$\frac{dx}{dt} =t^2-6t$

$\int dx = \int (t^2-6t)dt$

$x = \frac{t^3}{3}-6\frac{t^2}{2}+C_2$

At t=0, x=0

$0 = \frac{0^3}{3}-6(\frac{0^2}{2})+C_2$

Therefore the value of the second constant is

$C_2 = 0$

$x = \frac{t^3}{3}-\frac{6t^2}{2}$

Calculate the distance traveled after 11 s

At $t=11s$

$x = \frac{11^3}{3}-6(\frac{11^2}{2})$

$x = 80.667m$

6 0

3 years ago

Most of the water on Earth is

e-lub [12.9K]

Answer:

3% of the earth's water is fresh. 2.5% of the earth's fresh water is unavailable: locked up in glaciers, polar ice caps, atmosphere, and soil; highly polluted; or lies too far under the earth's surface to be extracted at an affordable cost. 0.5% of the earth's water is available fresh water.

To break the numbers down, 96.5% of all the Earth's water is contained within the oceans as salt water, while the remaining 3.5% is freshwater lakes and frozen water locked up in glaciers and the polar ice caps. Of that fresh water, almost all of it takes the form of ice: 69% of it, to be exact.

As these charts and the data table show, the amount of water locked up in ice and snow is only about 1.7 percent of all water on Earth, but the majority of total freshwater on Earth, about 68.7 percent, is held in ice caps and glaciers. Source: Gleick, P. H., 1996: Water resources.

The earth has an abundance of water, but unfortunately, only a small percentage (about 0.3 percent), is even usable by humans. The other 99.7 percent is in the oceans, soils, icecaps, and floating in the atmosphere. Still, much of the 0.3 percent that is useable is unattainable.

Explanation:

I hope this answer help you.

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2 years ago

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