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Korolek [52]
2 years ago
11

A rocket burns fuel to create hot gases that explode violently out of the rocket engine. This explosion creates thrust. Thrust i

s a force that pushes the rocket upward. What force must thrust overcome in order to send a rocket up into space?
Physics
1 answer:
Lerok [7]2 years ago
5 0

Answer:

Thrust due to fuel consumption must overcome gravitational force from the Earth to send the rocket up into space.

Explanation:

From the concept of Escape Velocity, derived from Newton's Law of Gravitation, definition of Work, Work-Energy Theorem and Principle of Energy Conservation, which is the minimum speed such that rocket can overcome gravitational forces exerted by the Earth, and according to the Tsiolkovski's Rocket Equation, which states that thrust done by the rocket is equal to the change in linear momentum of the rocket itself, we conclude that thrust due to fuel consumption must overcome gravitational force from the Earth to send the rocket up into space.

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.a car increases its speed from 10 m/s to 20/s in 2.5. seconds calculate it’s acceleration
Mekhanik [1.2K]

Answer:

\boxed {\boxed {\sf 4\ m/s^2}}

Explanation:

Acceleration is the rate of change of an object with respect to time. It is the change in velocity over the time.

a= \frac{v_f-v_i}{t}

The car starts at 10 meters per second and increases to 20 meters per second in 2.5 seconds.

  • v_f= 20 m/s
  • v_i= 10 m/s
  • t= 2.5 s

Substitute the values into the formula.

a= \frac{ 20 \ m/s - 10 \ m/s}{2.5 \ s }

Solve the numerator.

a= \frac{10 \ m/s}{2.5 \ s}

Divide.

a= 4 \ m/s/s

a= 4\ m/s^2

The acceleration of the car is <u>4 meters per second squared.</u>

3 0
2 years ago
What is the thinnest soap film (excluding the case of zero thickness) that appears black when illuminated with light with a wave
Llana [10]

Explanation:

It is given that,

The thinnest soap film appears black when illuminated with light with a wavelength of 535 nm, \lambda=5.35\times 10^{-7}\ m

Refractive index, \mu=1.33

We need to find the thickness of soap film. The soap film appear black means there is an destructive interference. The condition for destructive interference is given by :

2t=m\dfrac{\lambda}{\mu}

t = thickness of film

m = 0,1,2....

\mu = refractive index

t=m\dfrac{\lambda}{2\mu}

t=\dfrac{\lambda}{2\mu}

For thinnest thickness, m = 1

t=1\times \dfrac{5.35\times 10^{-7}\ m}{2\times 1.33}

t=2.01\times 10^{-7}\ m

Hence, this is the required solution.

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3 years ago
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solniwko [45]

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5 0
3 years ago
Which one property of a star will determine the rest of the characteristics of that star's life?
Galina-37 [17]
 the characteristics are to make and element
8 0
3 years ago
Two stationary positive point charges, charge 1 of magnitude 3.00 nC and charge 2 of magnitude 1.80 nC , are separated by a dist
MA_775_DIABLO [31]

Answer: U = -4.97*10^-17 J

Explanation:

Potential Energy of point charges,

U = kqq• / r, where

U = Potential Energy

q, q• = value of electric charges

k = 8.99*10^9 N.m²/C² constant of proportionality

r = distance between two charges

a) first electric potential due to electric field of first charge

q = 3*10^-9 C

q• = q(electron) = -1.602*10^-19 C

r = 0.5 * 31 cm = 15.5 cm = 0.155 m

U1 = kqq•/r

U1 = (8.99*10^9 * 3*10^-9 * -1.602*10^-19) / 0.155

U1 = -4.32*10^-18 / 0.155

U1 = -2.79*10^-17 J

Second electric potential due to electric field of second charge

U2 = kqq•/r

U2 = (8.99*10^9 * 1.8*10^-9 * -1.602*10^-19) / 0.155

U2 = -2.59*10^-18 / 0.155

U2 = -1.67*10^-17 J

U = U1 + U2

U = -2.79*10^-17 + -1.67*10^-17

U = -4.46*10^-17 J

b) first electric potential due to electric field of the first charge

q = 3*10^-9 C

q• = q(electron) = -1.602*10^-19 C

r = 10 cm = 0.1 m

U1 = kqq•/r

U1 = (8.99*10^9 * 3*10^-9 * -1.602*10^-19) / 0.1

U1 = -4.32*10^-18 / 0.1

U1 = -4.32*10^-17 J

Second electric potential to the electric field of second charge

q = 1.8*10^-9

q• = -1.602*10^-19 C

r = 50 - 10 = 40 cm = 0.4m

U2 = (8.99*10^9 * 1.8*10^-9 * -1.602*10^-19) / 0.4

U2 = -2.59*10^-18 / 0.4

U2 = -6.48*10^-18 J

U = U1 + U2

U = -4.32*10^-17 + -6.48*10^-18

U = -4.97*10^-17 J

5 0
3 years ago
Read 2 more answers
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