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Softa [21]
3 years ago
5

How many grams of solute are needed to make 125 mL of 2.50 M NH4Cl solution? Round to three significant digits.

Chemistry
1 answer:
Nookie1986 [14]3 years ago
4 0

Answer:

Mass = 16.7 g

Explanation:

Given data:

Volume  =  125 mL (125/1000 =0.125 L)

Molarity = 2.50 M

Mass in grams of solute = ?

Solution:

First of all we will calculate the number of moles:

<em>Molarity = number of moles solute / volume in litter</em>

2.50 M = Number of moles of solute/ 0.125 L

Number of moles of solute = 2.50 M × 0.125 L

Number of moles of solute = 0.313 mol

Grams of solute:

<em>Number of moles = mass / molar mass</em>

Mass = number of moles × molar mass

Mass =  0.313 mol × 53.5 g/mol

Mass = 16.7 g

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For a carbonate containing a kind of cation, we have that Option 1 is the correct answer: ammonium.

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4 0
2 years ago
A chemist prepares a solution of magnesium chloride MgCl2 by measuring out 49.mg of MgCl2 into a 100.mL volumetric flask and fil
Flura [38]

Answer:  Molarity of Cl^- anions in the chemist's solution is 0.0104 M

Explanation:

Molarity : It is defined as the number of moles of solute present per liter of the solution.

Formula used :

Molarity=\frac{n\times 1000}{V_s}

where,

n= moles of solute

Moles=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{0.049g}{95g/mol}=5.2\times 10^{-4}moles  

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Now put all the given values in the formula of molarity, we get

Molarity=\frac{5.2\times 10^{-4}moles\times 1000}{100ml}=5.2\times 10^{-3}mole/L

Therefore, the molarity of solution will be 5.2\times 10^{-3}mole/L

MgCl_2\rightarrow Mg^{2+}+2Cl^-

As 1 mole of MgCl_2 gives 2 moles of Cl^-

Thus 5.2\times 10^{-3}  moles of MgCl_2 gives =\frac{2}{1}\times 5.2\times 10^{-3}=0.0104

Thus the molarity of Cl^- anions in the chemist's solution is 0.0104 M

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3 years ago
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Answer:

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Answer:

fruit cake is the right ans

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3 years ago
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