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Arada [10]
3 years ago
13

When a firefighter slides down a pole his mechanical energy is transformed into thermal energy because of

Physics
2 answers:
Ivahew [28]3 years ago
7 0
His hands being on the pole creates the thermal energy because of the friction being made by sliding down the pole.
shutvik [7]3 years ago
5 0
His hands being on the pole creates the thermal energy because of the friction being made by sliding down the pole.
You might be interested in
Ran 300 meter in 40 seconds, what is the speed?
nignag [31]

Answer:

7.5

Explanation:

Speed= distance/ time

Speed= 300m/40sec

Speed= 7.5m/s

5 0
3 years ago
Briefly describe the formation of the planets from the solar nebula
saul85 [17]
<span>The formation of the Solar System began 4.6 billion years ago with the gravitational collapse of a small part of a giant molecular cloud. Most of the collapsing mass collected in the center, forming the Sun, while the rest flattened into a proto-planetary disk out of which the planets, moons, asteroids, and other small Solar System bodies formed.


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6 0
3 years ago
What did you notice about the angle of incidence and the angle of reflection?
Readme [11.4K]

Answer:

They are equal

Explanation:

angle of incidence = angle of reflection

6 0
2 years ago
Students in a chemistry class added 5g of zinc (Zn) to 50g of hydrochloric acid (HCl). A chemical reaction occurred that produce
PilotLPTM [1.2K]

Answer:

10. 36 g ZnCl2

Explanation:

Zn + 2HCl  -> ZnCl2 + H2

0.076 mol Zn

1.37 mol HCl

3 mol H2

Limiting reactant: Zn

1 mol Zn        -> 1 mol ZnCl2

0.076 mol Zn  ->x                         x= 0.076 mol ZnCl2=10.36 g

7 0
3 years ago
Two friends are playing a version of proton golf where the hole is marked by a single proton. The first friend reads his meter,
yarga [219]

Answer:

the electric field strength on the second one is 2.67 N/C.

Explanation:

the electric fiel on the first one is:

E1 = k×q/(r^2)

r^2 = k×q/(E1)

     = (9×10^9)×(q)/(24.0)

     = 375000000q

then the electric field on the second one is:

E2 = k×q/(R^2)

we know that R = 3r

                       R^2 = 9×r^2

E2 = k×q/(9×r^2)

     = k×q/(9×375000000q)

     = k/(9×375000000)

     = (9×10^9)/(9×375000000)

     = 2.67 N/C

Therefore, the electric field strength on the second one is 2.67 N/C.

5 0
3 years ago
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