The answer is B) pure water because pure water is a poor conductor of electricity.. thus a poor electrolyte
Answer:
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Answer:
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From the calculations, the pH of the buffer is 3.1.
<h3>What is the pH of the buffer solution?</h3>
The Henderson-Hasselbach equation comes in handy when we deal with the pH of a buffer solution. From that equation;
pH = pKa + log[(salt/acid]
Amount of the salt = 25/1000 * 0.50 M = 0.0125 moles
Amount of the acid = 75/1000 * 1.00 M = 0.075 moles
Total volume = ( 25 + 75)/1000 = 0.1 L
Molarity of salt = 0.0125 moles/0.1 L = 0.125 M
Molarity of the acid = 0.075 moles/0.1 L = 0.75 M
Given that the pKa of lactic acid is 3.86
pH = 3.86 + log( 0.125/0.75)
pH = 3.1
Learn more about pH:brainly.com/question/5102027
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