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2 years ago

What observations and inferences can you make from this picture?

Chemistry

2 answers:

Salsk061 [2.6K]2 years ago

6 0

I know they are fishing and there is an alligator in the lake. The alligator might grab the bait and attack the fishers.

Hope I helped!
Let me know if you need anything else!
~ Zoe

Liono4ka [1.6K]2 years ago

4 0

Answer:

Sample Response: The people are part of a softball team. They appear happy, they are showing the number one with their fingers, and they are holding a trophy. They probably won the softball league championship.

Explanation:

e2020

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What is the volume of an object that has a mass of 3.5 grams and has a density of 2.50 g/mL? Include units and proper sig figs l

jolli1 [7]

1.4mL

Explanation:

Given parameters:

Mass of object = 3.5g

density = 2.5g/mL

Unknown:

Volume of the object = ?

Solution:

Density is the mass per unit volume of a body. It is an intensive property that is the same for the same substances.

Density = $\frac{mass}{volume}$

since the volume is unknown; we make it the subject of the formula;

Volume = $\frac{mass}{density}$

Volume = $\frac{3.5}{2.5}$

Volume of the object = 1.4mL

learn more:

Density brainly.com/question/4825250

#learnwithBrainly

8 0

2 years ago

Normally the capital ÎGoÂ° for a reaction would be determined at standard temperature with each reactant at a concentration of 1

Arte-miy333 [17]

Answer:

d.-379 cal/mol

Explanation:

ΔG = ΔG⁰ + RT ln K

for equilibrium ΔG = 0

ΔG⁰ + RT ln K =0

ΔG⁰ = - RT ln K

PG ⇒ PEP

K = [ PEP ] / [ PG ]

= .68 / .32

= 2.125

ΔG⁰ = - 1.987 x 273 x ln 2.125

= - 409 Cal / mole

Option d is the nearest answer .

8 0

2 years ago

6832 J of heat energy is applied to 5.9 mol of water. If the original temperature of the water was 18.60C, the final temperature

sineoko [7]

Answer: The final temperature of the water will be $34.0^0C$

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

$Q=m\times c\times \Delta T$

Q = Heat absorbed= $6832$ Joules

m= mass of water = $5.9mol\times 18g/mol=106.2g$

c = specific heat capacity = $4.184J/g^0C$

Initial temperature of the water = $T_i$ = $18.6^0C$

Final temperature of the water = $T_f$ = ?

Putting in the values, we get:

$6832=106.2\times 4.184\times (T_f-18.6)$

$T_f=34.0^0C$

The final temperature of the water will be $34.0^0C$

8 0

2 years ago

A 32.8 g iron rod, initially at 22.4 C, is submerged into an unknown mass of water at 63.1 C, in an insulated container. The fin

laila [671]

Answer:

mass water = 32.4 g

Explanation:

specific heat iron = 0.450 J/g°C

specific heat water = 4.18 J/g°C

32.8 x 0.450 ( 59.1 - 22.4) + mass water x 4.18 ( 59.1- 63.1)=0

541.7 - mass water x 16.7 = 0

mass water = 32.4 g

3 0

2 years ago

Describe how water molecules can hydrate various substances

Georgia [21]

Answer:

A water molecule can react with the carbonyl group of an aldehyde or a ketone to form a substance known as a carbonyl hydrate, as shown in the first reaction below. The carbonyl hydrates usually form a very small percentage of the molecules in a sample of a specific aldehyde or ketone.

(Nice profile pic also UwU)

5 0

2 years ago