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Softa [21]
3 years ago
11

HELPPPPP

Chemistry
1 answer:
AVprozaik [17]3 years ago
4 0

A. electron, B. Nucleus

Proton is positive charge, electron is negative charge

proton weight, 1 AMU

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How many grams of magnesium nitride is required to produce 25.00 g of magnesium hydroxide?
Lesechka [4]

Answer:

25 grams of Mg(OH)2 will be produced by 14.424 gram of Mg3N2

Explanation:

The balanced equation is

Mg3N2 + 6H2O -> 3Mg(OH)2 + 2NH3

Molecular weight of magnesium nitride = 100.9494 g/mol

Molecular weight of magnesium hydroxide = 58.3197 g/mol

one mole of Mg3N2 produces three moles of 3Mg(OH)2

100.9494 g/mol of  Mg3N2 produces 3* 58.3197 g/mol of Mg(OH)2

1 gram of Mg3N2 produces

\frac{3* 58.3197}{100.9494 } \\1.733grams of Mg(OH)2

Or 1.733 grams of Mg(OH)2 will be produced by 1 gram of Mg3N2

25 grams of Mg(OH)2 will be produced by 14.424 gram of Mg3N2

6 0
3 years ago
Upon combustion, a 1.3109 g sample of a compound containing only carbon, hydrogen, and oxygen produces 3.2007 g<img src="https:/
Ivenika [448]

Answer:

The answer to your question is:   C₃H₃O  This is my answer.

Explanation:

Data

Sample = 1.3109 g

CxHyOz

CO₂ = 3.2007 g

H₂O = 1.3102 g

Empirical formula = ?

MW CO2 = 44 g

MW H2O = 18 g

For Carbon

                                     44 g -------------------- 12 g

                                     3.2007 g ------------    x

                                      x = (3.2007 x 12) / 44

                                      x = 0.8729 g of Carbon

                                     12 g of C --------------  1 mol

                                     0.8729 g --------------  x

                                     x = (0.8729 x 1) / 12

                                     x = 0.0727 mol of Carbon

For Hydrogen

                                 18 g ---------------------- 1 g

                              1.3102 g -------------------  x

                                   x = (1.3102 x 1) / 18

                                  x = 0.0727 g of Hydrogen                                      

                                  1 g ------------------------ 1 mol

                                  0.0727g ----------------  x

                                  x = (0.0727 x 1)/1

                                  x = 0.0727 mol of Hydrogen

For oxygen

                    g of Oxygen = g of sample - g of Carbon - g of hydrogen

                    g of Oxygen = 1.3109 - 0.8709 - 0.0727

                    g of Oxygen = 0.3673

                                  16 g of Oxygen ------------- 1 mol of O

                                  0.3673 g ---------------------   x

                                   x = (0.3673 x 1)/ 16

                                   x = 0.0230 mol of Oxygen

Divide by the lowest number of moles

Carbon              0.0727 / 0.023  = 3.1  ≈ 3

Hydrogen         0.0727 / 0.023 = 3.1  ≈ 3

Oxygen             0.0230 / 0.023 = 1

                                        C₃H₃O

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D: is the anwser that your looking for

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it the same side with the other side you fellow the other side

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