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Softa [21]
3 years ago
11

HELPPPPP

Chemistry
1 answer:
AVprozaik [17]3 years ago
4 0

A. electron, B. Nucleus

Proton is positive charge, electron is negative charge

proton weight, 1 AMU

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Which of the following actions will lead to an increase in pressure?
MatroZZZ [7]
By decreasing n we can increase presure because decrease in n will shift equilibrium to either forward or reverse direction
3 0
3 years ago
Ensure you write the states of the reactants and products.
slamgirl [31]
<h3>Answer:</h3>

Phosphoric acid reacts with magnesium hydroxide to produce magnesium phosphate and water via the following reaction:

2H3PO4 + 3Mg(OH)2 → Mg3(PO4)2 + 6H2O

(solid) (solid) (solid) (liquid)

<h3>Explaination:</h3>

This is a typical neutralization reaction of an acid with a base to form a salt and water. The reaction is exothermic, gives off heat,

ΔH < 0 , and may be balanced by adding balancing numbers in front, ie adding molecules, in order to ensure that the total number of atoms of each element is the same on the left and right hand sides of the equation.

Doing so we obtain :

2H3PO4 + 3Mg(OH)2 → Mg3(PO4)2 + 6H2O

(solid) (solid) (solid) (liquid)

<h3>hope it helps :)</h3>
6 0
3 years ago
Read 2 more answers
Which of the following is in intensive property a. mass b. magnetism c shape D. volume
lisov135 [29]

Answer:

b. Magnetism (sorry im very late)

Explanation:

Intensive properties do not depend on size, no matter what it doesn't. For example, magnetism, density, melting and boiling points, and color. All of those support intensive property.

3 0
3 years ago
Given: C + O2 → CO2 Bond Bond Energy (kJ/mol) C=O 799 O=O 494 Calculate the enthalpy change for the chemical reaction. The chang
aliya0001 [1]

Answer:

-1104 kJ/mol

Explanation:

The change in the enthalpy of a reaction is equal to the difference between: the sum of the enthalpy changes of the bonds broken and the sum of the enthalpy changes of the bonds formed.

The bonds broken correspond to the cleavage of bonds of the reactants, the bonds formed correspond to the bonds of the products:

  • we only break oxygen O=O bond, since carbon is not bonded to anything;
  • we form two C=O bonds in carbon dioxide.

Therefore, the enthalpy change is calculated by:

\Delta H^o = 1 mol\cdot 494 kJ/mol - 2 mol\cdot 799 kJ/mol = -1104 kJ/mol

3 0
3 years ago
What is the mass of 5.76 moles of NaPO4
dolphi86 [110]

use the formula that was given to you


7 0
3 years ago
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