Complete question:
Two 10-cm-diameter charged rings face each other, 21.0 cm apart. Both rings are charged to +40.0 nC. What is the electric field strength at the midpoint between the two rings ?
Answer:
The electric field strength at the mid-point between the two rings is zero.
Explanation:
Given;
diameter of each ring, d = 10 cm = 0.1 m
distance between the rings, r = 21.0 cm = 0.21 m
charge of each ring, q = 40 nC = 40 x 10⁻⁹ C
let the midpoint between the two rings = x
The electric field strength at the midpoint between the two rings is given as;
Therefore, the electric field strength at the mid-point between the two rings is zero.
Answer:
Explanation:
I-V graph always represent a straight line
Answer:
#See solution for details.
Explanation:
-Chemical energy in the battery is converted into Electrical Energy which powers up the phone.
-The electrical energy is then converted to Light Energy when the phone is powered up, this is seen through the lightening up of the phone screen.
-During phone calls, the electrical energy is further converted to Sound Energy to allow for transmission of audio signals.
- As we continue to use the phone, the electrical energy is converted into heat energy which we feel due to an overheating battery.
-The cycle then repeats itself again whenever a phone is charged.
Iron rich minerals in rock pointed in one direction the switch to the exact opposite direction. I'd say that what supports this idea is that Earth's magnetic field goes through pole reversals.<span>
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