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lidiya [134]
3 years ago
5

For a hypothetical reaction the linear Arrhenius equation is LaTeX: y=-15035x+41.45y = − 15035 x + 41.45. What is the activation

energy for this reaction?
Group of answer choices
125 kJ/mol
15 kJ/mol
-1.8 kJ/mol
-125 kJ/mol
1810 kJ/mol
Chemistry
1 answer:
Y_Kistochka [10]3 years ago
4 0

Arrhenius equation is LaTeX: y=-15035x+41.45y = − 15035 x + 41.45. What is the activation energy for this reaction is described below.

Explanation:

When the rates are equal and the concentration of reactants and products are constant not equal. Other like activation energies and potential energies are not necessary for equilibrium.

The activation energies of the forward and reverse reactions ,the rates of the forward and reverse reactions are  25 minutes ago.

For a hypothetical reaction the linear Arrhenius equation is LaTeX: y=-15035x+41.45y = − 15035 x + 41.45

15kj/mol is the answer..

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Calculate the ΔG°rxn using the following information at 298K. 2 HNO3(aq) + NO(g) → 3 NO2(g) + H2O(l) ΔG°rxn = ? ΔH°f (kJ/mol) -2
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Answer:

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In the reaction:

2 HNO3(aq) + NO(g) → 3 NO2(g) + H2O(l)

ΔH°rxn = 3×ΔHfNO2 + ΔHfH2O - (2×ΔHfHNO3 + ΔHfNO)

ΔH°rxn = 3×33.2kJ/mol + (-285.8kJ/mol) - (2×-207.0kJ/mol + 91.3kJ/mol)}

ΔH°rxn = 136.5kJ/mol

And S°:

S°rxn = 3×S°NO2 + S°H2O - (2×S°HNO3 + S°NO)

ΔH°rxn = 3×0.2401kJ/molK + (0.0700kJ/molK) - (2×0.146kJ/molK + 0.2108kJ/molK)

ΔH°rxn = 0.2875kJ/molK

And replacing in (1) at 298K:

ΔG°rxn = 136.5kJ/mol - 298K×0.2875kJ/molK

<em>ΔG°rxn = +50.8 kJ/mol</em>

<em />

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