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Answer:
The amount of work done required to stretch spring by additional 4 cm is 64 J.
Explanation:
The energy used for stretching spring is given by the relation :
.......(1)
Here k is spring constant and x is the displacement of spring from its equilibrium position.
For stretch spring by 2.0 cm or 0.02 m, we need 8.0 J of energy. Hence, substitute the suitable values in equation (1).

k = 4 x 10⁴ N/m
Energy needed to stretch a spring by 6.0 cm can be determine by the equation (1).
Substitute 0.06 m for x and 4 x 10⁴ N/m for k in equation (1).

E = 72 J
But we already have 8.0 J. So, the extra energy needed to stretch spring by additional 4 cm is :
E = ( 72 - 8 ) J = 64 J
Answer:
1. A glass of water at 80°C because the more heat it will recieve, the more temperature increases. Heat is a sort of energy so the more it is heated, the more energy the water will recieve. So in comparison to 20°C, 80°C has more energy in it because it has a higher temperature.
2. An aluminium can at 30°C because the more heat it will recieve, the more temperature increases. Heat is a sort of energy so the more it is heated, the more energy the aluminium will recieve. So in comparison to 20°C, 30°C has more energy in it because it has a higher temperature.
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Answer:
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Answer:
43.41 mm
Explanation:
Given:
thickness of sheet, t = 6 mm
Force exerted by punch, F = 45 KN
Average shearing stress, T = 55 MPa
From average shearing stress T = Force F / Area A
Hence area = force/stress =45000/ 55 =
From area = pi*diameter*thickness
diameter = area/(pi* thickness)
= 818.18/(3.142*6)
= 43.41 mm