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zloy xaker [14]
2 years ago
15

A cyclist is traveling along a road due east at 12 km/h and wind is blowing from south-west at 5 km/h . find the velocity of the

wind relative to the cyclist.
Physics
1 answer:
Bogdan [553]2 years ago
3 0

The velocity of the wind relative to the cyclist is determined as -15.3 km i - 3.5 km j.

<h3>Velocity of the wind relative the cyclist</h3>

The speed of the wind in x - direction and y - direction is calculated as follows;

v(w/c) = - 5 km(cos 45)i - 5km(sin45)j

v(w/c) = [- 3.5 i - 3.5 j ] km

velocity of wind with respect to cyclist = (-12 km i - 3.5 km i) - 3.5 km j

velocity of wind with respect to cyclist = -15.3 km i - 3.5 km j

Thus, the velocity of the wind relative to the cyclist is determined as -15.3 km i - 3.5 km j.

Learn more about relative velocity here: brainly.com/question/17228388

#SPJ1

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seraphim [82]

Answer:

The answer is a 4.2m

Explanation:

Given data

Please see attached the rough drawing for your reference.

From the drawing, you ran 18m west and 2.4m south

The displacement is

= 1.8+2.4

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8 0
3 years ago
The CEO, ellen misk, left her martian office but accidentally left a cylindricall can of coke (3.1 inches in diameter, 5.42 inch
iren2701 [21]

Answer:

Specific Gravity = 0.378

Explanation:

First, we will find the force exerted by the can on the table. This force will be equal to the weight of the can:

Pressure = Force/Area = Weight/Area

Weight = Pressure*Area

where,

Area = πdiameter²/4 = π[(3.1 in)(0.0254 m/1 in)]²/4 = 4.8 x 10⁻³ m²

Weight = (510 N/m²)(4.8 x 10⁻³ m²)

Weight = 2.48 N

Now, the weight is given as:

Weight = mg

2.48 N = m(9.8 m/s²)

m = (2.48 N)/(9.8 m/s²)

m = 0.25 kg

Now, we calculate volume of can:

Volume = (Area)(Height) = (4.8 x 10⁻³ m²)(5.42 in)(0.0254 m/1 in)

Volume = 6.6 x 10⁻⁴ m³

Hence, the density of can will be:

Density of Can = m/Volume = 0.25 kg/6.6 x 10⁻⁴ m³

Density of Can = 378.32 kg/m³

So, the specific gravity of Can will be:

Specific Gravity = Density of Can/Density of Water

Specific Gravity = (378.32 kg/m³)/(1000 kg/m³)

<u>Specific Gravity = 0.378</u>

8 0
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The horse on a carousel is 3.5m from the central axis.A. If the carousel rotates at 0.13 rev/s , how long does it take the horse
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Answer:

a. 15.4 seconds

b. 0.455 m/s

Explanation:

a. The carousel rotates at 0.13 rev/s.

This means that it takes the carousel 1 sec to make 0.13 of an entire revolution.

This means that time it will take to make a complete revolution is:

1 / 0.13 = 7.7 seconds

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2 * 7.7 = 15.4 seconds

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\omega = v / r

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0.13 = v / 3.5

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Answer:

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