What two spheres are being pulled by the fires of gravity

Predict the products and then balance the equation

Aneli [31]

$\qquad \qquad\huge \underline{\boxed{\sf Answer}}$

Here's the balanced equation for given Double displacement reaction ~

$\sf Pb(NO_3)_2 +2 \: KI = PbI_2 +2 \: KNO_3$

The products fored are : Lead Iodide ( PbI2 ) and Potassium Nitrate ( KNO3 )

4 0

2 years ago

Read 2 more answers

To answer this question, you will need to write the balanced equation and set up a BCA table. Using appropriate rounding rules,

Elenna [48]

Water decomposes when electrolyzed to produce hydrogen and oxygen gas. If 2.5 grams of water were decomposed 1.04 grams of oxygen will be formed.

BCA table:

2 $H_{2}$ O ⇒ $H_{2}$ + $O_{2}$

B 0.13 0 + 0

C -0.13 0.065 + 0.065

A 0 0.065

Explanation:

Balanced equation for water decomposition into hydrogen and oxygen gases

2 $H_{2}$ O ⇒ $H_{2}$ + $O_{2}$

B 0.13 0 + 0

C -0.13 0.065 + 0.065

A 0 0.065

Number of moles of water = $\frac{mass}{atomic mass of 1 mole}$

mass = 2.5 grams

atomic mass= 18 grams

number of moles can be known by putting the values in the formula,

n = $\frac{2.5}{18}$

= 0.13 moles

2 moles of water gives one mole of oxygen on decomposition

so, 0.13 moles of water will give x moles of oxygen on decompsition

$\frac{1}{2}$ = $\frac{x}{0.13}$

x = 0.065 moles of oxygen will be formed.

moles to gram will be calculated as

mass =number of moles x atomic mass

= 0.065 x 16

= 1.04 grams of oxygen.

7 0

4 years ago

Which correctly lists the types of matter, in terms of their atoms, in order from least tightly packed to most tightly packed?

SSSSS [86.1K]

Answer:

D

Explanation:

gas are well separated with no regular arrangement and spreaded all over. liquid are close together with no regular arrangement and slightly spreaded. solid are tightly packed, usually in a regular pattern and not spreaded at all.

3 0

3 years ago

Read 2 more answers

The gas cyclobutane, C4H8(g), can be used in welding. When cyclobutane is burned in oxygen, the reaction is: C4H8(g) + 6 O2(g)4

Snowcat [4.5K]

Answer:

a

$\Delta H^o _{rxn} = -2568.9 \ kJ$

b

$H = 350 JK^{-1}$

c

$T_{max} = 32.4 ^o C$

Explanation:

From the question we are told that

The reaction of cyclobutane and oxygen is

$C_4H_8_{(g)} + 6 O_2_{(g)} \to 4 CO_2_{(g)} + 4 H_2O_{(g)}$

ΔH°f (kJ mol-1) : C4H8(g) = 27.7 ; CO2(g) = -393.5 ; H2O(g) = -241.8 ΔH° = kJ

Generally ΔH° for this reaction is mathematically represented as

$\Delta H^o _{rxn} = [[4 * \Delta H^o_f (CO_2_{(g)} ) + 4 * \Delta H^o_f(H_2O_{(g)} ] -[\Delta H^o_f (C_2H_6_{(g)} + 6 * \Delta H^o_f (O_2_{(g)}) ] ]$

=> $\Delta H^o _{rxn} = [[4 * (-393.5) + 4 * (-241.8) ] -[ 27.7 + 6 * 0]$

=> $\Delta H^o _{rxn} = -2568.9 \ kJ$

Generally the total heat capacity of 4 mol of CO2(g) and 4 mol of H2O(g), using CCO2(g) = 37.1 J K-1 mol-1 and CH2O(g) = 33.6 J K-1 mol-1. C = J K-1 is mathematically represented as

$H = [ 4 * C_{CO_2_{(g)}} + 6* C_{CH_2O_{(g)}}]$