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3 years ago

Covert 60 mph to SI mks units

Physics

1 answer:

Flauer [41]3 years ago

7 0

26.82m/s

Explanation:

Given:

speed = 60mph

problem: convert to m/s

To solve this problem, we have to find the right and appropriate conversion factor which equals to 1 to multiply this unit with:

we are converting:

miles to meters

hours to seconds

1.609km = 1mile

1000m = 1km

60s = 1 min

60 min = 1hr

Now to convert from mph to m/s

60 x $\frac{mi}{hr}$ x $\frac{1.609km}{1mi} x \frac{1000m}{1km} x \frac{1hr}{60min} x \frac{1m}{60s}$

= 26.82m/s

learn more:

Conversion brainly.com/question/1548911

#learnwithBrainly

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3 years ago

The maximum speed limit on interstate 10 is 75 miles per hour. how many meters per second is this

Dvinal [7]

Answer:

Explanation:

Given the maximum speed limit on interstate 10 as 75 miles per hour, to get the speed in meter per seconds, we need to convert the given speed to meter per seconds.

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3 years ago

38.4 mol of krypton is in a rigid box of volume 64 cm^3 and is initially at temperature 512.88°C. The gas then undergoes isobari

kolbaska11 [484]

Answer:

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Explanation:

Using the Ideal Gases Law yoy have for pressure:

$P_{1} = \frac{n_{1} R T_{1} }{V_{1} }$

where:

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R is the universal gas constant: 8,314 J/mol K

T is the temperature in Kelvin

V is the volumen in cubic meters

Given that the amount of material is constant in the process:

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$P_{1} = P_{2}$

$\frac{n R T_{1} }{V_{1} } = \frac{n R T_{2} }{V_{2} }$

$\frac{T_{1} }{V_{1} } = \frac{T_{2} }{V_{2} }$

$V_{2} = \frac{T_{2} V_{1} }{T_{1} }$

Replacing : $T_{1} =786 K, T_{2} =1209 K, V_{1} = 64 cm^{3}$

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Replacing on the ideal gases formula the pressure at this piont is:

$P_{2} = 3,92 * 10^{9} Pa$

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$T = \frac{P V }{n R }$

For the second process you have that $T_{2} = T_{3}$ So:

$\frac{P_{2} V_{2} }{n R } = \frac{P_{3} V_{3} }{n R }$

$P_{2} V_{2} = P_{3} V_{3}$

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2 years ago

Tarik winds a small paper tube uniformly with 183 turns 183 turns of thin wire to form a solenoid. The tube's diameter is 9.49 m

Rufina [12.5K]

<h2>Answer:</h2>

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<h2>Explanation:</h2>

The inductance (L) of a coil wire (e.g solenoid) is given by;

L = μ₀N²A / l --------------(i)

Where;

l = the length of the solenoid

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A = 3.142 x 0.00949² / 4

A = 7.1 x 10⁻⁵m²

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