bullet's change in kinetic energy=<span> The work done by the resistive force "F" </span>
<span>-Fx = 0 - (1/2)mv^2 </span>
<span>F(.12) = (1/2)(.01)(160000) </span>
<span>F = 6666.7 N </span>
<span>change in momentum; </span>
<span>- (6666.7)t = 0 - (.01)(400) </span>
<span>t = .0006 s </span>
<span>the bullets acceleration is </span>
<span>a = - F/m = - 666667 m/s2 </span>
<span>So plot the graph; </span>
v = 400 - (666667)t
hope this helps
Answer:
Please provide an image to help clarify
Explanation:
thanks :)
Known :
m1 = m
m2 = 3m1 = 3m
a1 = 30.0 m/s²
Solution :
Net force of the object is constant, so :
F1 = F2
m1 • a1 = m2 • a2
(m)(30.0 m/s²) = (3m)(a2)
a2 = 10 m/s²
Answer:
The gauge pressure is equal to 147 kPa.
Explanation:
The pressure exerted by fluid is given by :
Where
is density of water
h is height
So, put all the values,
or
P = 147 kPa
So, the gauge pressure is equal to 147 kPa.
