they all are measurements
doubling both would increase it
Since the slowest instruction in the SCA executes in 12.5 ns, the maximum system clock frequency is 80 MHz
To answer the question, we need to know what frequency is.
<h3>What is frequency?</h3>
Frequency is the number of oscillations per second of a wave.
It is given by f = 1/T where T = period of wave
Now, given that the slowest instruction in the SCA executes in t = 12.5 ns, we need to calculate maximum system clock frequency, f.
<h3>What is the maximum system clock frequency?</h3>
So, f = 1/t
= 1/12.5 ns
= 1/(12.5 × 10⁻⁹ s)
= 1/12.5 × 10⁹ Hz
= 0.08 × 10⁹ Hz
= 80 × 10⁻³ × 10⁹ Hz
= 80 × 10⁶ Hz
= 80 MHz
So, the maximum system clock frequency is 80 MHz
Learn more about maximum system clock frequency here:
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Answer:
A but not 100% certain.
Explanation:
you can eliminate C since it doesn't mention gravity, and B says gravity is pushing up on the orange. I think it is A because friction is going against the orange because it has to pass through the air, and that creates friction. I think that is the reason why things burn up when they enter the earths atmosphere.
Answer:
Force of Rope = 122.5 N
Force of Rope = 480.2N
Explanation:
given data
length = 3.00 m
mass = 25.0 kg
clown mass = 79.0 kg
angle = 30°
solution
we get here Force of Rope on with and without Clown that is
case (1) Without Clown
pivot would be on the concrete pillar so Force of Rope will be
Force of Rope × 3m = (25kg)×(9.8ms²)×(1.5m)
solve it and we get
Force of Rope = 122.5 N
and
case (2) With Clown
so here pivot is still on concrete pillar and clown is standing on the board middle and above the centre of mass so Force of Rope will be
Force of Rope × 3m = (25kg+73kg)×(9.8ms²)×(1.5m)
solve it and we get
Force of Rope = 480.2N
Answer:
This is the information I can provide. I hope it helps
Explanation:
Frequency is measured in units of hertz (Hz) which is equal to one occurrence of a repeating event per second. The period is the duration of time of one cycle in a repeating event, so the period is the reciprocal of the frequency.
