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frosja888 [35]
3 years ago
13

Câu 1: Trong phân tử este (X) no, đơn chức, mạch hở có thành phần oxi chiếm 36,36 % khối lượng. Số đồng phân bố

Chemistry
1 answer:
enyata [817]3 years ago
3 0
B..............................
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if you mixed 72.9g hydrochloric acid(aq) with 150g silver acetate(aq), what would be the limiting reagent?​
horsena [70]

Answer:

                      Silver Acetate would be the Limiting Reagent.

Explanation:

                    The balance chemical equation for the given double displacement reaction is as;

                            HCl + AgC₂H₃O₂ → AgCl + HC₂H₃O₂

Step 1: <u>Calculate Moles of Starting Materials:</u>

Moles of HCl:

                      Moles  =  Mass / M.Mass

                      Moles  =  72.9 g / 36.46

                      Moles =  1.99 moles

Moles of AgC₂H₃O₂:

                      Moles  =  150 g / 166.91 g/mol

                      Moles  =  0.898 moles

Step 2: <u>Find out Limiting reagent as:</u>

According to balance chemical equation.

              1 mole of HCl reacts with  =  1 mole of AgC₂H₃O₂

So,

         1.99 moles of HCl will react with  =  X moles of AgC₂H₃O₂

Solving for X,

                     X =  1.99 mol × 1 mol / 1 mol

                     X =  1.99 mol of AgC₂H₃O₂

Hence, to completely consume 1.99 moles of Hydrochloric acid we will require 1.99 moles of Silver Acetate, But, we are provided with only 0.898 moles of Silver Acetate. This means Silver Acetate will consume first in the reaction therefore, it is the LIMITING REAGENT.

8 0
3 years ago
What sample size (grams) of Na3PO4 (FW 164.00) known to be 50.00% pure should be used to consume exactly 40.00 mL of 0.1000 M HC
Mkey [24]

Answer:

0.109 g.

Explanation:

Equation of the reaction:

Na3PO4 + 3HCl --> 3NaCl + H3PO4

Number of moles of HCl = molar concentration × volume

= 0.1 × 0.04

= 0.004 mol.

By stoichiometry, 1 mole of Na3PO4 neutralises 3 moles of HCl. Therefore, number of moles of Na3PO4 = 0.004/3

= 0.0013 mol

Mass of Na3PO4 = molar mass × number of moles

= 0.0013 × 164

= 0.219 g

Since 50% of Na3PO4 was present in the sample. Let 100 g be the total mass of the substance

= 0.219 × 50 g/100 g

= 0.109 g.

3 0
3 years ago
Please help this is due tomorrow!
lbvjy [14]
I had this same question on one of are worksheets is D I can’t really explain it but the answer is D
7 0
3 years ago
Iron filings could be separated from sand using _______.
Deffense [45]

Answer:

A. a magnet

Explanation:

Iron fillings could be separated from sand using a magnet

3 0
3 years ago
If energy increasing or decreasing as you go from a solid to a liquid
Gelneren [198K]
The energy increases because the molecules in water move faster
8 0
3 years ago
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