Replacement of methyl groups of camphor is a reduction mechanism. Camphor is a bridged bi-cyclic compound. If you observe the structure of camphor the methyl group is placed with one carbon bridge (7, 7) and two carbon bridge (1). Attack from face of one carbon bridge is termed as exo attack whereas from face of two carbon bridge is termed as endo attack. So replacement will lead to mix of both and formation of two stereo isomers.
Reduction mechanism is often shown with a U-shaped arrow pointing the attack by ion such as in nucleophilic addition reaction.
Answer:
1.209g of MgO participates
Explanation:
In this problem, we have 0.030 moles of MgO that participates in a particular reaction.
And we are asked to solve for the mass of MgO that participates, that means, we need to convert moles to grams.
To convert moles to grams we need to use molar mass of the compound:
<em>1 atom of Mg has a molar mass of 24.3g/mol</em>
<em>1 atom of O has a molar mass of 16g/mol</em>
<em />
That means molar mass of MgO is 24.3g/mol + 16g/mol = 40.3g/mol
And mass of 0.030 moles of MgO is:
0.030 moles MgO * (40.3g/mol) =
<h3>1.209g of MgO participates</h3>
False , they form water or ice crystals
The chemical bonds in CH4 are all single bonds. C only can bond 4 times because it needs 8 electrons in it's outer shell and only has four right now. The bonds represented are all single bonds because there are two electrons present on each side of the carbon. Two electrons, in this case, equals one bond.
Gold have a greater mass
<h3>Further explanation </h3>
Density is a quantity derived from the mass and volume
Density is the ratio of mass per unit volume
The unit of density can be expressed in g/cm³ or kg/m³
Density formula:
ρ = density
m = mass
v = volume
