All categories

4 years ago

A loop with a break in it that prevents current form flowing is called a(n) blank circuit

Physics

1 answer:

sergij07 [2.7K]4 years ago

3 0

Answer: it is called a open circuit

Explanation:

You might be interested in

Please help!!! I will mark brainliest asap, this is due in 10 minutes!

VARVARA [1.3K]

Answer:

speed

(distance per time)

Kathy is faster btw

4 0

3 years ago

Read 2 more answers

For stars in the main sequence, which color of stars tend to have higher absolute brightness?

PilotLPTM [1.2K]

White star and dwarf

6 0

3 years ago

Read 2 more answers

Four identical masses of 2.5 kg each are located at the corners of a square with 1.0-m sides. What is the net force on any one o

Ghella [55]

Answer:

F=8.0*10^{-10}N

Explanation:

See the attached file for the masses distributions

The force between two masses at distance r is expressed as

$F=\frac{Gm_{1}m_{2} }{r^{2} }\\ G=Gravitional constant \\$

since the masses are of the same value, the above formula can be reduce to

$F=\frac{Gm^{2}}{r^{2} }\\$

using vector notation,Let use consider the force on the lower left corner of the mass due to the upper left side of the mass is

$F_{12} =\frac{Gm^{2}}{r^{2} }j\\$

The force on the lower left corner of the mass due to the lower right side of the mass is

$F_{14} =\frac{Gm^{2}}{r^{2} }i\\$

The force on the lower left corner of the mass due to the upper right side of the mass is

$F_{13} =\frac{Gm^{2}}{d^{2} }cos\alpha i +\frac{Gm^{2}}{d^{2} }sin\alpha j\\$

The net force can be express as

$F=\frac{Gm^{2}}{r^{2} }j +\frac{Gm^{2}}{r^{2} }i +\frac{Gm^{2}}{d^{2} }cos\alpha i +\frac{Gm^{2}}{d^{2} }sin\alpha j\\\\F=Gm^{2}[\frac{1}{r^{2}}+ \frac{1}{d^{2}cos\alpha }]i + Gm^{2}[\frac{1}{r^{2}}+ \frac{1}{d^{2}sin\alpha }]j\\\alpha=45^{0}, G=6.67*10^{-11}Nmkg^{-2}$

if we insert values we arrive at

$F=6.67*10^{-11}*2.5^{2}[\frac{1}{1^{2}}+ \frac{1}{\sqrt{2}^{2}cos45 }]i + 6.67*10^{-11}*2.5^{2}[\frac{1}{1^{2}}+ \frac{1}{\sqrt{2}^{2}sin45}]j\\F=5.643*10^{-10}i+5.643*10^{-10}j$

if we solve for the magnitude, we arrive at

$F=5.643*10^{-10}i+5.643*10^{-10}j \\F=\sqrt{(5.643*10^{-10})^{2} +(5.643*10^{-10})}^{2} \\F=8.0*10^{-10}$

Hence the net force on one of the masses is

$F=8.0*10^{-10}N$

8 0

3 years ago

Câu 5. Một vật dao động điều hòa với phương trình x = 20cos(10pit +pi/2) (cm). Xác định thời điểm đầu tiên vật đi qua vị trí có

NARA [144]

Answer:

Explanation:lớp 12 à

6 0

3 years ago

What is the escape velocity on the Venus ? Venus' mass 4.90*10^ 24 kg and radius is 6.86 * 10 ^ 6 * m

gtnhenbr [62]

The escape velocity on Venus is 9761 m/s

Explanation:

The escape velocity from a planet is the speed that an object on the surface of that planet must have in order to completely escape the gravitational field of the planet.

Mathematically, it is calculated as

$v=\sqrt{\frac{2GM}{R}}$