The heat capacity of the silver spoon at the given temperature difference is 817.65 J.
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Heat capacity of the silver spoon</h3>
The heat capacity of theb silver spoon is the quantity of heat absorbed by the silver spoon. The heat capacity of the silver spoon at the given temperature difference is calculated as follows;
Q = mcΔθ
where;
- m is mass of the spoon
- c is specific heat capacity of silver = 0.237 J/g⁰C
- Δθ is change in temperature
Q = 50 x 0.237 x (89 - 20)
Q = 817.65 J
Thus, the heat capacity of the silver spoon at the given temperature difference is 817.65 J.
Learn more about heat capacity here: brainly.com/question/16559442
Answer:
Friction force is the force that one object exerts in another when the two rub against each other. Most of the time, friction force opposes the motion of an object.
Explanation:
Answer:
1807.56 kJ
Explanation:
Parameters given:
Current, I = 8.9A
Time, t = 4.7hrs = 4.7 * 3600 = 16920 secs
Voltage, V = 12V
Electrical energy is given as:
E = I*V*t
Where I = Current
V = Voltage/Potential differenxe
t = time in seconds.
E = 8.9 * 12 * 16920
E = 1807056 J = 1807.056 kJ
Answer: ZnSO4 + Li2CO3 = ZnCO3 + Li2SO4 - Chemical Equation Balancer
Equation is already balanced.
Explanation: ZnSO4 + Li2CO3 = ZnCO3 + Li2SO4
