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Anna71 [15]
3 years ago
7

4.2 mol of monatomic gas A interacts with 3.2 mol of monatomic gas B. Gas A initially has 9500 J of thermal energy, but in the p

rocess of coming to thermal equilibrium it transfers 600 J of heat energy to gas B.
What is the initial thermal energy of B?
Physics
1 answer:
Komok [63]3 years ago
6 0

Answer:

14657.32 J

Explanation:

Given Parameters ;

Number of moles mono atomic gas A ,   n 1  =  4 .2 mol

Number of moles mono atomic gas B ,   n 2  =  3.2mol

Initial energy of gas A ,   K A  =  9500  J

Thermal energy given by gas A to gas B ,   Δ K  =  600 J

Gas constant   R  = 8.314  J / molK

Let  K B  be the initial energy of gas B.

Let T be the equilibrium temperature of the gas after mixing.

Then we can write the energy of gas A after mixing as

(3/2)n1RT = KA - ΔK

⟹ (3/2) x 4.2 x 8.314 x T = 9500 - 600

T = (8900 x 3 )/(2x4.2x8.314) = 382.32 K

Energy of the gas B after mixing can be written as

(3/2)n2RT = KB + ΔK

⟹ (3/2) x 3.2 x 8.314 x 382.32 = KB + 600

⟹ KB = [(3/2) x 3.2 x 8.314 x 382.32] - 600

⟹ KB = 14657.32 J

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ra1l [238]

Answer:

The third particle should be at 0.0743 m from the origin on the negative x-axis.

Explanation:

Let's assume that the third charge is on the negative x-axis. So we have:

E_{1}+E_{3}-E_{2}=0

We know that the electric field is:

E=k\frac{q}{r^{2}}

Where:

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  • r is the distance from the charge to the point

So, we have:

k\frac{q_{1}}{r_{1}^{2}}+k\frac{q_{3}}{r_{3}^{2}}-k\frac{q_{2}}{r_{2}^{2}}=0

Let's solve it for r(3).

\frac{3.01}{0.0429^{2}}+\frac{9.03}{r_{3}^{2}}-\frac{6.02}{0.0429^{2}}=0

r_{3}=0.0743\:  

Therefore, the third particle should be at 0.0743 m from the origin on the negative x-axis.

I hope it helps you!

 

3 0
2 years ago
what is the energy of a single photon of ultraviolet light with a wavelength of 30.0 nm? 1 nm=10^-9 m
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From the planks equation
E=hv
V= c/ wave length
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4 0
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A hard rubber ball on a string is being used as a pendulum. When you first look at the pendulum, the ball is being held to one s
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Answer:

<h2>Total thermal energy for all air molecules is 59.54 J</h2>

Explanation:

As we know that the ball comes to rest finally so here we can say that

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So here we have

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E_{th} = (6.2 kg)(9.8 m/s^2)(0.98 m)

So here we have

E_{th} = 59.54 J

So all the gravitational potential energy of the ball will convert into thermal energy of air molecules which is equal to 59.54 J

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polet [3.4K]

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Since we were give mass and acceleration, therefore magnitude of force will be

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8 0
3 years ago
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Brrunno [24]

Answer:

C) ions or free radicals, highly reactive species that can cause undesirable effects in living tissue.

Explanation:

Ionizing radiation is a type of energy released by atoms in the form of electromagnetic waves or particles

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• The cell may lose its ability to reproduce itself.

• The cell’s genetic code (i.e., the DNA) may be damaged such that future copies of the cell are altered, which may result in cancerous growth.

• The absorption of radiation by a cell may have no adverse effects.

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Hence the correct answer is C.

7 0
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