A 10.00-kilogram block slides along a horizontal, frictionless surface at 12.0 meters per second for 6.00 seconds. The magnitude
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Answer:
The force does the ceiling exert on the hook is 269.59 N
Explanation:
Applying the second Newton law:
F = m*a
From the attached diagram, the net force in object 1 is:
In object 2:
Adding the two equations:
(eq. 1)
The torque:
Where
I = moment of inertia
α = angular acceleration
If the linear acceleration is
Torque due the tension is equal:
Substituting torque, mass, in equation 1, the expression respect the acceleration is:
Where
W₁ = 75 N
W₂ = 125 N
W = 80 N
The net force is:
