A 10.00-kilogram block slides along a horizontal, frictionless surface at 12.0 meters per second for 6.00 seconds. The magnitude
1 answer:
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Answer:
The centripetal acceleration of the stone is 5 m/s²
Explanation:
The length of the string to which the stone is attached, r = 1 m
The speed with which the string is rotated, v = 5 m/s
The centripetal acceleration, , is given as follows;
Therefore, the centripetal acceleration of the stone found as follows;
The centripetal acceleration of the stone, = 5 m/s².
Initial height of platform is 15.87m or 16m.
Answer:
q₁ = + 1.25 nC
Explanation:
Theory of electrical forces
Because the particle q₃ is close to two other electrically charged particles, it will experience two electrical forces and the solution of the problem is of a vector nature.
Known data
q₃=5 nC
q₂=- 3 nC
d₁₃= 2 cm
d₂₃ = 4 cm
Graphic attached
The directions of the individual forces exerted by q1 and q₂ on q₃ are shown in the attached figure.
For the net force on q3 to be zero F₁₃ and F₂₃ must have the same magnitude and opposite direction, So, the charge q₁ must be positive(q₁+).
The force (F₁₃) of q₁ on q₃ is repulsive because the charges have equal signs ,then. F₁₃ is directed to the left (-x).
The force (F₂₃) of q₂ on q₃ is attractive because the charges have opposite signs. F₂₃ is directed to the right (+x)
Calculation of q1
F₁₃ = F₂₃
We divide by (k * q3) on both sides of the equation
q₁ = + 1.25 nC
Answer:
Temperature, T = 3.62 kelvin
Explanation:
It is given that,
Total number of gas molecules,
Her body is converting chemical energy into thermal energy at a rate of 125 W, P = 125 W
Time taken, t = 6 min = 360 s
Energy of a gas molecules is given by :
, k is Boltzmann constant
T = 3.62 K
So, the temperature increases by 3.62 kelvin. Hence, this is the required solution.