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vodomira [7]
3 years ago
12

A 10.00-kilogram block slides along a horizontal, frictionless surface at 12.0 meters per second for 6.00 seconds. The magnitude

of the block's momentum is
Physics
1 answer:
earnstyle [38]3 years ago
4 0

Answer:

120 kg m/s

Explanation:

The magnitude of the momentum of an object is given by

p=mv

where

m is the mass of the object

v is its speed

For the block in this problem,

m = 10.0 kg (mass of the block)

v = 12.0 m/s (speed of the block)

Therefore the magnitude of the block's momentum is

p=(10.0 kg)(12.0 m/s)=120 kg m/s

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PLEASE HELP ME WITH THIS ONE QUESTION
Kitty [74]

Answer:

Q = 282,000 J

Explanation:

Given that,

The mass of liquid water, m = 125 g

Temperature, T = 100°C

The latent heat of vaporization, Hv = 2258 J/g.

We need to find the amount of heat needed to vaporize 125 g of liquid water. We can find it as follows :

Q=mH_v\\\\Q=125\ g\times 2285\ J/g\\\\Q=282250\ J

or

Q = 282,000 J

So, the required heat is 282,000 J .

6 0
2 years ago
1. How does an area’s weather differ from the area’s climate? (1 point). A.Weather involves temperature and precipitation and cl
makkiz [27]
1. "Weather is the area’s day-to-day conditions and climate is the area’s average conditions" is how <span>an area’s weather differ from the area’s climate. The correct option among all the options given in the question is option "D".

2. </span>All of the following factors contribute to Earth’s climate except longitude. <span>The correct option among all the options given in the question is the second option.</span>
4 0
3 years ago
Read 2 more answers
Helen adjusts the armature of an electric generator by increasing the number of coils around the iron core. What is Helen most l
Luba_88 [7]

Answer:

D

Explanation:

Got it right on the edge quiz

8 0
3 years ago
Read 2 more answers
A girl pulls on a 10 kg wagon with a constant force of 20 N. What is the wagon’s acceleration
andreev551 [17]

Answer:

2

Explanation:

İf system ideal ( no frictional force )

Fnet=m.a

20=10.a

a=2m/s2

6 0
2 years ago
A flat, 179 179 ‑turn, current‑carrying loop is immersed in a uniform magnetic field. The area of the loop is 4.41 cm 2 4.41 cm2
Alecsey [184]

Answer:

The value of the magnetic field is  B =0.1423T

Explanation:

From the question we are told that

              The number of turns is  N = 179

               The area of the loop is A = 4.41cm^2 = \frac{4.41}{10000} = 0.000414m

                 The angle is  \theta  = 59^o

               The torque  is  \tau =2.25 * 10^{- 5} N

                The current is  I = 2.49\ mA

The torque acting on the current carry loop is  mathematically represented as

                     \tau = B * I * N * A * sin \theta

Where is the magnitude of the magnetic filed

Making B the subject

                     B= \frac{\tau}{I * N * A * sin\theta}

Substituting values

                    B = \frac{2.25*10^{-5}}{2.49*10^{-3} * 179 * 0.000414 * sin (59)}

                       =0.1423 T

4 0
3 years ago
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