Question

A 10.00-kilogram block slides along a horizontal, frictionless surface at 12.0 meters per second for 6.00 seconds. The magnitude of the block's momentum is

Answer 1

Answer:

120 kg m/s

Explanation:

The magnitude of the momentum of an object is given by

$p=mv$

where

m is the mass of the object

v is its speed

For the block in this problem,

m = 10.0 kg (mass of the block)

v = 12.0 m/s (speed of the block)

Therefore the magnitude of the block's momentum is

$p=(10.0 kg)(12.0 m/s)=120 kg m/s$