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faltersainse [42]
3 years ago
14

What happens to the magnetic domains in a material when the material is placed in a strong magnetic field?

Physics
1 answer:
Allisa [31]3 years ago
6 0
If it is diamagnetic then it magnetise opposite to magnetic field
if paramagnetic it weekly magnetise in direction of magnetic field
if ferromagnetic it strongly magnetise in direction of magnetic field
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PLEASE HELP I NEED TO TURN IT IN IN AN HOUR ITLL GIVE YOU POINTS PLS PLEASE
miv72 [106K]

Answer:

  1. 17.95025
  2. 172.3995

Explanation:

1.

\mathrm{The\:solution\:for\:Long\:Division\:of}\:\frac{2.995}{0.16685}\:\\\mathrm{is}\:17.95025

2.

\mathrm{Multiply\:without\:the\:decimal\:points,\:then\:put\:the\:decimal\:point\:in\:the\:answer}\\\\910\times\:18945=17239950\\\\910\mathrm{\:has\:}0\mathrm{\:decimal\:places}\\0.18945\mathrm{\:has\:}5\mathrm{\:decimal\:places}\\\\\mathrm{Therefore,\:the\:answer\:has\:}5\mathrm{\:decimal\:places}\\\\=172.39950\\\\Refine\\=172.3995

5 0
3 years ago
What system carries food to cells though the blood ?
irinina [24]
"Circulatory system" does that, as all about transportation of blood within the body comes under it's work

Hope this helps!
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3 years ago
What can be known about electrons?
BlackZzzverrR [31]
Electrons carry a negative charge.
8 0
3 years ago
During a biology lab, students use a small knife called a scalpel to examine a large cricket. One student is accidentally cut by
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All except the first one. I just took the test.
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3 years ago
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A heat pump used to heat a house runs about one-third of the time. The house is losing heat at an average rate of 22,000 kJ/h. I
Natali5045456 [20]

The power that heat pump draws when running will be 6.55 kj/kg

A heat pump is a device that uses the refrigeration cycle to transfer thermal energy from the outside to heat a building (or a portion of a structure).

Given a heat pump used to heat a house runs about one-third of the time. The house is losing heat at an average rate of 22,000 kJ/h and if the COP of the heat pump is 2.8

We have to determine the power the heat pump draws when running.

To solve this question we have to assume that the heat pump is at steady state

Let,

Q₁ = 22000 kj/kg

COP = 2.8

Since heat pump used to heat a house runs about one-third of the time.

So,

Q₁ = 3(22000) = 66000 kj/kg

We known the formula for cop of heat pump which is as follow:

COP = Q₁/ω

2.8 = 66000 / ω

ω = 66000 / 2.8

ω = 6.66 kj/kg

Hence the power that heat pump draws when running will be 6.55 kj/kg

Learn more about heat pump here :

brainly.com/question/1042914

#SPJ4

5 0
2 years ago
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