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faltersainse [42]
2 years ago
14

What happens to the magnetic domains in a material when the material is placed in a strong magnetic field?

Physics
1 answer:
Allisa [31]2 years ago
6 0
If it is diamagnetic then it magnetise opposite to magnetic field
if paramagnetic it weekly magnetise in direction of magnetic field
if ferromagnetic it strongly magnetise in direction of magnetic field
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The river bank can expand due to the water breaking apart which can cause sediment to move and change/erode

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mixas84 [53]

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Correct answer: The fourth claim

Explanation:

No claim is most accurate but if you have to choose the best from the bad one, it's fourth - Its height decreased as its motion increased.

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An alpha particle can be produced in certain radioactive decays of nuclei and consists of two protons and two neutrons. The part
Varvara68 [4.7K]

Answer:

Explanation:

charge, q = 2e = 2 x 1.6 x 10^-19 C = 3.2 x 10^-19 C

mass, m = 4 u = 4 x 1.661 x 10^-27 kg = 6.644 x 10^-27 kg

Radius, r = 4.5 cm = 0.045 m

Magnetic field, B = 1.20 T

(a) Let the speed is v.

v=\frac{Bqr}{m}

v=\frac{1.20\times 3.2\times 10^{-19}\times 0.045}{6.644\times 10^{-27}}

v = 2.6 x 10^6 m/s

(b) Let T be the period of revolution

T=\frac{2\pi r}{v}

T=\frac{2\times 3.14\times 0.045}{2.6\times 10^{6}}

T = 1.09 x 10^-7 s

(c) The formula for the kinetic energy is

K=\frac{B^{2}\times q^{2}\times r^{2}}{2m}

K=\frac{\left ( 1.20\times 3.2 \times 10^{-19}\times 0.045 \right )^{2}}{2\times 6.644\times 10^{-27}}

K = 2.25 x 10^-14 J

(d) Let the potential difference is V.

K = qV

V = \frac{K}{q}

V= \frac{2.25\times 10^-14}{3.2\times 10^{-19}}

V = 70312.5 V

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3 years ago
What is the difference between condensation and conduction
aniked [119]

Answer:

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Explanation:

Their a difference....... A huge One

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3 years ago
A particle of charge q moving through a magnetic field B experiences the force where v is the velocity of the particle. Show tha
MrRa [10]

Answer:

       dx/Dt x B . x  =0

Explanation:

Let's calculate the work and the magnetic force, the expression for magnetic force is

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Bold indicate vector quantities, the expression for the job is

         W = F. X

Let's replace in this equation

       W = q v x B . X

The definition of speed is

      v =  dX / dt

With what work is left

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As we can see the vector product gives us a vector perpendicular to dX and its scalar product by X of zero

Second part

   The speed a vector and although the magnitude is constant the change of direction implies a change in the speed.

   Let's calculate the magnitudes of speed (speed)

       F = qv B sin θ

       F = ma

       q v B sin θ = ma

       a = qvB / m senT

     

This acceleration is perpendicular to the magnetic field and the velocity, so it does not change if magnitude but its direction, it is directed to the center of the circle.

   | v | = q vB/m sin θ

3 0
3 years ago
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