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Harrizon [31]
3 years ago
5

Write an expression for a transverse harmonic wave that has a wavelength of 2.5 m and propagates to the right with a speed of 13

.8 m/s . The amplitude of the wave is 0.14 m , and its displacement at t=0 and x=0 is 0.14 m .
Physics
1 answer:
lyudmila [28]3 years ago
3 0

Answer:

y = 0.14 Cos\left ( 2.512x-34.66t \right )

Explanation:

wavelength, λ = 2.5 m

speed, v = 13.8 m/s

Amplitude, A = 0.14 m

The general equation of the transverse harmonic wave which is travelling right is given by

y = A Sin\left ( \frac{2\pi }{\lambda } (x - vt)+\phi \right  )

where, Ф is phase

At t = 0, x = 0 , y = 0.14 m

0.14 = 0.14 Sin Ф

Ф = π/2

So, the equation is

y = 0.14Sin\left ( \frac{2\pi }{2.5 } (x - 13.8t)+\frac{\pi }{2} \right  )

y = 0.14 Cos\left ( 2.512x-34.66t \right )

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Answer:

Explanation:

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putting the values

\frac{1}{1.8} =(1.38-1)(\frac{1}{.5} -\frac{1}{r_2})

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r₂ = 1.86 cm .

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b )

object distance u = 25 cm

focal length of convex lens  f  = 1.8 cm

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\frac{1}{v} - \frac{1}{u} = \frac{1}{f}

\frac{1}{v} - \frac{1}{-25} = \frac{1}{1.8}

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c )

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5 0
3 years ago
A +0.2 µC charge is in an electric field. What happens if that charge is replaced by a +0.4 µC charge?
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Explanation:

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                 U = qV

Since, the electric potential is directly proportional to the charge. Hence, when 0.2 \mu C tends to replaced by 0.4 \mu C then charge is increased by a factor of 2. Hence, the electric potential energy is doubled.

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4 0
3 years ago
A baseball is hit at ground level. The ball reaches its maximum height above ground level 3.0 s after being hit. Then 2.5 s afte
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Answer:

Part a)

H = 44.1 m

Part b)

y = 13.48 m

Part c)

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Explanation:

Part a)

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x = v_x t

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Answer:

0.021 V

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E = - \frac{N*\Delta \phi}{\Delta t}  

<u>Where:</u>

<em>N = is the number of turns = 1   </em>

<em>ΔΦ = ΔB*A                                            </em>

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<em>A = is the loop of wire area = πr² = πd²/4 </em>

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I hope it helps you!

8 0
3 years ago
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Marta_Voda [28]

Answer:

A. ls sensitive to heat

this is correct answer

I hope it's helpful for you.......

4 0
3 years ago
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