Answer:
The net ionic equation for the given reaction :

Explanation:
...[1]
..[2]
...[3]

Replacing
, NaI and
in [1] by usig [2] [3] and [4]

Removing the common ions present ion both the sides, we get the net ionic equation for the given reaction [1]:

Answer:
H₂SO₄ (aq) + 2LiOH (aq) ⇒ Li₂SO₄ (aq) + 2H₂O (l)
Explanation:
This is an acid-base reaction, so we know the products are going to a salt/ionic compound and water.
Answer:
The correct answer will be "
".
Explanation:
We have:
Moles of solute (Na₂Co₃) = 
= 
= 
Now,
The volume of the solution will be:
⇒ 
∴ 
The formula to find the concentration will be:
⇒ 
On substituting the given values, we get
⇒ 
⇒ 
Answer:
, product favoured
Explanation:
Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.
Net ionic equation : In the net ionic equations, we do not include the spectator ions in the equations.
When hydrochloric acid react with potassium cyanide, then it gives potassium chloride and hydrocyanic acid as products.
The complete ionic equation will be:
The net ionic equation will not contain spectator ions which are
and
:

The reaction is product favoured.