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AnnyKZ [126]
4 years ago
12

A scientist is studying a previously unknown chemical reaction. She concludes that it is exothermic. What must the scientist hav

e observed?
The reaction released heat.
The reaction formed a gas.
The reaction sped up when a catalyst was added.
The reaction caused the container to get cold.
Chemistry
2 answers:
SVEN [57.7K]4 years ago
6 0
I think the correct answer from the choices listed above is the first option. She concluded that the reaction is an exothermic one because t<span>he reaction released heat. Exothermic is when heat goes out of the system. The opposite is referred to as an endothermic reaction.</span>
Ann [662]4 years ago
6 0
A. <span>The reaction released heat.</span>
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Answer:

The net ionic equation for the given reaction :

3Mn^{2+}(aq)+2PO_4^{3-}(aq)\rightarrow Mn_3(PO_4)_2(s)

Explanation:

3MnI_2(aq)+2Na_3PO_4_2(aq)\rightarrow Mn_3(PO_4)_2(s)+6NaI(aq)...[1]

MnI_2(aq)\rightarrow Mn^{2+}(aq)+2I^-(aq)..[2]

Na_3PO_4(aq)\rightarrow 3Na^{+}(aq)+PO_4^{3-}(aq)...[3]

NaI(aq)\rightarrow Na^+(aq)+I^-(aq)

Replacing MnI_2(aq) , NaI and Na_3PO_4(aq) in [1] by usig [2] [3] and [4]

3Mn^{2+}(aq)+6I^-(aq)+6Na^{+}(aq)+2PO_4^{3-}(aq)\rightarrow Mn_3(PO_4)_2(s)+6Na^+(aq)+6I^-(aq)

Removing the common ions present ion both the sides, we get the net ionic equation for the given reaction [1]:

3Mn^{2+}(aq)+2PO_4^{3-}(aq)\rightarrow Mn_3(PO_4)_2(s)

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4 years ago
4.8 L sample of helium gas contains 0.22 moles of helium - How many additional moles of herum gas must be added to the sample to
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H2SO4(aq)+LiOH(aq)→ Express your answer as a chemical equation. Identify all of the phases in your answer. Enter noreaction if t
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Answer:

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Answer:

The correct answer will be "9.45\times 10^{-5} \ mol/L".

Explanation:

We have:

Moles of solute (Na₂Co₃) = 18.9 \mu \ mol

                                           = 18.9\times 10^{-6}

                               1 \mu \ mol = 10^{-6} \ mol

Now,

The volume of the solution will be:

⇒  0.200 \ L

∴ {1 \ mL=0.001 \ L}

The formula to find the concentration will be:

⇒  Concentration = \frac{moles \ of \ solute \ (mol)}{Volume \ of \ solution \ (L)}

On substituting the given values, we get

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8 0
3 years ago
Write the net ionic equation for the reaction between hydrochloric acid and potassium cyanide. Do not include states such as (aq
zhannawk [14.2K]

Answer: H^++CN^-\rightarrow HCN, product favoured

Explanation:

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we do not include the spectator ions in the equations.

When hydrochloric acid react with potassium cyanide, then it gives potassium chloride and hydrocyanic acid as products.

The complete ionic equation will be:

H^++Cl^-+K^++CN^-\rightarrow K^++Cl^-+HCN

The net ionic equation will not contain spectator ions which are K^+ and Cl^-:

H^++CN^-\rightarrow HCN

The reaction is product favoured.

 

5 0
3 years ago
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