Question

A bat hits a moving baseball. If the bat delivers a net eastward impulse of 1.5 N-s and the ball starts with an initial horizontal velocity of 3.8 m/s to the west and leaves with a 4.9 m/s velocity to the east, what is the mass of the ball (in grams)? (NEVER include units in the answer to a numerical question.)

Answer 1

Answer:

The mass of the ball is 5866 g.

Explanation:

Given that,

Impulse = 1.5 N.s

Velocity to the west = 3.8 m/s

Velocity to the east = 4.9 m/s = -4.9 in to the west

We need to calculate the mass of the ball

Using formula of impulse

$I = p_{i}-P_{f}$

$I=m(v_{i}-v_{f})$

$m=\dfrac{v_{i}-v_{f}}{I}$

Where, $v_{i}$ = initial velocity

$v_{f}$ =final velocity

m = mass of ball

Put the value into the formula

$m=\dfrac{3.9-(-4.9)}{1.5}$

$m=5.866\ kg$

$m = 5866\ g$

Hence, The mass of the ball is 5866 g.