3 years ago

The area of the eye where there is no version

Physics

1 answer:

fomenos3 years ago

4 0

It is called the fovea centralis.

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A 12-kg projectile is launched with an initial vertical speed of 20 m/s. It rises to a maximum height of 18 m above the launch p

kirill115 [55]

Answer:

Change in mechanical energy, $\Delta E=283.2\ J$

Explanation:

It is given that,

Mass of the projectile, m = 12 kg

Speed of the projectile, v = 20 m/s

Maximum height, h = 18 m

Initially, the projectile have only kinetic energy. it is given by :

$K=\dfrac{1}{2}mv^2$

$K=\dfrac{1}{2}\times 12\ kg\times (20\ m/s)^2$

K = 2400 J

Finally, it have only potential energy. it is given by :

P = mgh

$P=12\ kg\times 9.8\ m/s^2\times 18\ m$

P =2116.8 J

The change in mechanical energy is given by :

$\Delta E=K-P$

$\Delta E=2400-2116.8$

$\Delta E=283.2\ J$

So, the change in mechanical energy is 283.2 J. Hence, this is the required solution.

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3 years ago

Que es un patrimonio histórico Nacional

Musya8 [376]

Answer:

yes

Explanation

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3 years ago

After a 50-kg person steps from a boat onto the shore, the boat moves away with a speed of 0.70 m/s with respect to the shore. I

Svetradugi [14.3K]

Answer:

M=125 kg

v=1.75 m/s

Explanation:

From the law of linear momentum

P =mv

Case 1 50*V =M* 0.7 equation 1

50*V =(M+50)* 0.5 equation 2

equating 1 and 2

M* 0.7=(m+50)* 0.5

0.2 M= 25

M=125 kg

Putting value of M in equation 1

50*V =125*0.7

V=1.75 m/s

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3 years ago

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An Alaskan rescue plane traveling 37 m/s drops a package of emergency rations from a height of 134 m to a stranded party of expl

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vf = - 46 m/s since up is positive

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Meme on newtons law of motion (should me made ur self not from any searh engine)

k0ka [10]

He will be a pilot and he will fly the plane over bridges fewwww

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2 years ago

The area of the eye where there is no version​

The area of the eye where there is no version