It's the last option again. You have 1 linear factor (3<em>x</em>) and 2 copies of a quadratic factor (<em>x</em>² + 10), and the partial fractions with the quadratic factor need to have a linear polynomial in the numerator.
Answer:
Step-by-step explanation:
y + 1 = -9(x + 9)
y + 1 = -9x - 81
y = -9x - 82
answer is A
Consider the function

, which has derivative

.
The linear approximation of

for some value

within a neighborhood of

is given by

Let

. Then

can be estimated to be

![\sqrt[3]{63.97}\approx4-\dfrac{0.03}{48}=3.999375](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B63.97%7D%5Capprox4-%5Cdfrac%7B0.03%7D%7B48%7D%3D3.999375)
Since

for

, it follows that

must be strictly increasing over that part of its domain, which means the linear approximation lies strictly above the function

. This means the estimated value is an overestimation.
Indeed, the actual value is closer to the number 3.999374902...
the gardener would need (1 + 1/6) liters of water to water the whole garden.
<h3>How much water would the gardener need to water the whole garden?</h3>
Here we know that the gardener needs 1/3 of a liter of water to water 2/7 of a garden.
Then we have the relation:
1/3 L = 2/7 of a garden.
Now, we want to get a "1 garden" in the right side of the equation, then we can multiply both sides by (7/2), so we get:
(7/2)*(1/3) L = (7/2)*(2/7) of a garden
(7/6)L = 1 garden.
(1 + 1/6) L = 1 garden
This means that the gardener would need (1 + 1/6) liters of water to water the whole garden.
If you want to learn more about fractions:
brainly.com/question/11562149
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