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TiliK225 [7]
3 years ago
13

Which of the following is not an example of a NATURAL polymer?

Chemistry
1 answer:
kondaur [170]3 years ago
5 0
Sugar is not a polymer
You might be interested in
Which gas is produced when dilute hydrochloric acid is added to a reactive metal.
Digiron [165]

Hydrogen gas is produced when dilute hydrochloric acid is added to a reactive metal.

Balanced molecular equation of sodim metal with hydrochloric acid:

2Na(s) + 2HCl(aq) → 2NaCl(aq) + H₂(g).

Ionic equation: 2Na(s) + 2H⁺(aq) + 2Cl⁻(aq) → 2Na⁺ + 2Cl⁻(aq) + H₂(g).

Net ionic equation: 2Na(s) + 2H⁺(aq) → 2Na⁺(aq) + H₂(g).

Sodium is oxidized from oxidation number 0 (Na) to oxidation number +1, hydrogen is reduced from oxidation number +1 to oxidation number 0 (hydrogen gas H₂).

Another example:

Balanced chemical equation: Zn(s) + 2HCl(aq) → ZnCl₂(aq) + H₂(g)

Word equation: zinc + hydrochloric acid → zinc chloride + hydrogen gas

More about hydrogen gas:brainly.com/question/24433860

#SPJ4

7 0
1 year ago
Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial ch
mamaluj [8]

Answer:

Explanation:

From the given information:

The equation for the reaction can be represented as:

2SO_2 + O_2 \to 2SO_3

The I.C.E table can be represented as:

                     2SO₂              O₂                   2SO₃

Initial:             14                  2.6                     0

Change:        -2x                -x                      +2x

Equilibrium:   14 - 2x          2.6 - x                2x

However, Since the amount of sulfur trioxide gas to be 1.6 mol.

SO₃ = 2x,

then x = 1.6/2

x = 0.8 mol

For 2SO₂; we have 14 - 2x

= 14 - 2(0.8)

= 14 - 1.6

= 12.4 mol

For O₂; we have 2.6 - x

= 2.6 - 1.6

= 1.0 mol

Thus;

[SO₂] = moles / volume = ( 12.4/50) = 0.248 M ,

[O₂] = 1/50 = 0.02 M ,  

[SO₃] = 1.6/50 = 0.032 M

Kc = [SO₃]² / [SO₂]² [O₂]

= ( 0.032²) / ( 0.248² x 0.02)

= 0.8325

Recall that; the equilibrium constant for the reaction 2SO_2 + O_2 \to 2SO_3 = 0.8325;

If we want to find:

SO_2 + \dfrac{1}{2}O_2 \to SO_3

Then:

K_c = (0.8325)^{1/2}

\mathbf{K_c = 0.912}

Since no temperature is given to use in the question, it will be impossible to find the final temperature of the mixture.

7 0
3 years ago
What happens in a reduction half-reaction?
Marta_Voda [28]
The answer is elements gain electrons. Oxidation reduction is elements lose electrons. And oxygen is added/lost can be a type of oxidation/reduction reaction.
3 0
3 years ago
Read 2 more answers
Help! 7th Grade Math!
vagabundo [1.1K]

Answer:

D

Explanation: Trust me

6 0
3 years ago
How many grams of H2O are needed to produce 150 g of Mg(OH)2? (Molar mass: H2O = 18.02 g/mol; Mg(OH)2 = 58.33 g/mol )
Nuetrik [128]

Answer:

92.6

Explanation:

6 mol x 18.02 g of H2o --> 3 mol x 58.33 g  Mg(OH)2

108.12 g of h2o --> 174.99 of Mg(OH)2

g of H2O is 150 g of Mg(OH)2

150g x 108.12g / 174.99 =

92.67

7 0
3 years ago
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