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Zolol [24]
3 years ago
10

An end of a light wire rod is bent into a hoop of radius r. The straight part of the rod has length l; a ball of mass M is attac

hed to the other end of the rod. The pendulum thus formed is hung by the hoop onto a revolving shaft. The coefficient of friction between the shaft and the hoop is µ. Find the equilibrium angle between the rod and the vertical.
Physics
1 answer:
Roman55 [17]3 years ago
8 0

Answer:

arcsin(\frac{R\mu}{(R+l)\sqrt{\mu^2+1}})

Explanation:

By the Law of Sines,

sin \theta = \frac{sin \phi R}{ l + R}

From Newton's Law,

mg = N\sqrt{\mu^2+1}

And the last equation again from Newton's Law,

\mu N = mgsin\phi

Then if we collect all equations together,

\mu N = mgsin\phi = N\sqrt{\mu^2+1}sin\phi\\

sin\theta = \frac{\mu R}{ (l + R)\sqrt{\mu^2+1}}

Thus,

\theta = arcsin(\frac{R\mu}{(R+l)\sqrt{\mu^2+1}})

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Answer:

Oppositely charged particles attract each other, while like particles repel one another. Electrons are kept in the orbit around the nucleus by the electromagnetic force, because the nucleus in the center of the atom is positively charged and attracts the negatively charged electrons.

Explanation:

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Calculate the power of an engine which can supply 60kg of energy per minute​
Nutka1998 [239]

Answer:

1 Watt

Explanation:

Power (P) = w / Δt

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3 years ago
Find the total electric charge of 2.5 kg of electrons. Express your answer using two significant figures.
zimovet [89]

Answer : The total electric charge of electrons is, -4.4\times 10^{11}C

Explanation:

Answer : The number of electrons transferred are, 4.68\times 10^{20}

Explanation :

First we have to calculate the number of electrons.

Number of electrons = \frac{\text{Total mass of electrons}}{\text{Mass of one electron}}

Mass of 1 electron = 9.1\times 10^{-31}kg

Total mass of electron = 2.5 kg

Number of electrons = \frac{2.5kg}{9.1\times 10^{-31}kg}

Number of electrons = 2.75\times 10^{30}

Now we have to calculate the total electric charge of electrons.

Formula used :

Q=ne\\\\n=\frac{Q}{e}

where,

n = number of electrons transferred = 2.75\times 10^{30}

Q = charge on electrons = ?

e = charge on 1 electron = -1.602\times 10^{-19}C

Now put all the given values in the above formula, we get:

2.75\times 10^{30}=\frac{Q}{-1.602\times 10^{-19}C}

Q=-4.4\times 10^{11}C

Thus, the total electric charge of electrons is, -4.4\times 10^{11}C

4 0
3 years ago
What is the power involved in lifting a 1.0-kg object 1.0 m in 1.0 s??
MAVERICK [17]
Mass  = 1kg 
Distance  = 1m 
Time = 1s
Force= Mass x Acceleration due to graviy
          =  1 x 9.8 = 9.8
Velocity = Distance  / time
              = 1 / 1 =1m/s
Power = Force x velocity
           = 9.8 x 1 = 9.8 W
5 0
3 years ago
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