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jek_recluse [69]
3 years ago
11

What is the currency for performing work and what is its unit?

Physics
1 answer:
ExtremeBDS [4]3 years ago
6 0
The currency for performing work is called : Energy

And Energy's unit of measurement is : Joule

The amount of energy you've inputed will always equal the output.

For example, in order to do a 500 joules of work, you need 500 joules of energy
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Based on the data collected, explain why a launch angle of 30 degrees (HIGH HORIZONTAL VELOCITY & SMALL TIME OF FLIGHT) will
Gennadij [26K]

Answer:

Explanation:

The horizontal distance traveled by the projectile is given by the formula

R=\frac{u^{2}Sin2\theta }{g}

The formula for the time of flight is given by

T = \frac{2u Sin\theta }{g}

Case I: when the launch angle is 30°

So, R_{1}=\frac{u^{2}Sin60 }{g}

R_{1}=\frac{0.866u^{2}}{g}

Horizontal velocity = u Cos 30 = 0.866 u

T_{1} = \frac{2u Sin30 }{g}=\frac{u}{g}

Case II: when the launch angle is 60°

R_{2}=\frac{u^{2}Sin120}{g}

R_{2}=\frac{0.866u^{2}}{g}

Horizontal velocity = u Cos 60 = 0.5 u

T_{1} = \frac{2u Sin60 }{g}=\frac{1.73 u}{g}

By observing the case I and case II, we conclude that

R1 = R2

Horizontal velocity 1 > Horizontal velocity 2

T1 < T2

5 0
3 years ago
Why is velocity most important in space launch?
Debora [2.8K]
Escape velocity is the velocity an object needs to escape the gravitational influence of a body if it is in free fall, i.e. no force other than gravity acts on it. Your rocket is not in free fall since it is using its thruster to maintain a constant velocity so the notion of "escape velocity" does not apply to it.
6 0
4 years ago
Read 2 more answers
In her hand, a softball pitcher swings a ball of mass 0.245 kg around a vertical circular path of radius 59.8 cm before releasin
GuDViN [60]

Answer:

The velocity is v_b = 20.17 \ m/s

Explanation:

From the question we are told that

   The mass of the ball is  m = 0.245 \ kg

   The radius is  r =  59.8 \  cm  =  0.598 \ m

   The force is  F =  30.9 \ N

   The speed of the ball is  v = 16.0 \ m/s.

Generally the kinetic energy at the top of the circle is mathematically represented as

    K_t  =  \frac{1}{2} *  m  *  v^2

=> K_t  =  \frac{1}{2} *  0.245   *  16.0 ^2  

=> K_t  =  31.36 \ J  

Generally the work done by the force applied on the ball from the top to the bottom  is mathematically represented as

       W =  F *  d

Here  d is the length of  a semi - circular arc which is mathematically represented as

       d =  \pi * r

So

      W =  30.9 *  0.598

      W = 18.48 \ J

Generally the kinetic energy at the bottom is mathematically represented as

      K_b  =  \frac{1}{2} *  m *  v_b^2

=>    K_b  =  \frac{1}{2} *  0.245  *  v_b^2

=>   K_b  =  0.1225  *  v_b^2

From the law of energy conservation

     K_t +  W  =K_b

=>    31.36+  18.48 = 0.1225  *  v_b^2

=>    v_b = 20.17 \ m/s

3 0
3 years ago
What is a diffraction grating? What is a diffraction grating? A device used to grate cheese and other materials A musical instru
hammer [34]

Answer:

An opaque object with many closely spaced slits

Explanation:

Diffraction grating is an opaque object which will have many close slits on it

Each slit will allow the light wave pass through it which incident on it.

So here each slit will behave like a secondary source which will transmit the light and the superposition of light is then observed on the screen

These large number of slits on the object is combined known as diffraction grating.

By the superposition of waves due to grating we will have pattern of maximum and minimum intensity on the screen and this intensity if highest at the mid point of screen and then decreases as we move away

5 0
3 years ago
A tertiary source is the most desirable source for a researcher to use. True or false
Kaylis [27]

The statement ‘A tertiary source is the most desirable source for a researcher to use’ is false. It should be that your source is primary because it is more reliable and is related to the research you have been working on.

6 0
3 years ago
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