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OleMash [197]
3 years ago
12

• Define and describe in detail (and in your own words) ultrasound and infrasound

Chemistry
1 answer:
qaws [65]3 years ago
4 0

Answer:

Human ears can hear sound waves that vibrate in the range from about 20 times a second (a deep rumbling noise) to about 20,000 times a second (a high-pitched whistling). (Children can generally hear higher-pitched sounds than their parents, because our ability to hear high frequencies gets worse as we get older.) Speaking more scientifically, we could say that the sounds we can perceive have a frequency ranging from 20–20,000 hertz (Hz). A hertz is a measurement of how often something vibrates and 1 Hz is equal to one vibration each second. The human voice makes sounds ranging from a few hundred hertz to a few thousand hertz.

Suppose you could somehow hit a drum-skin so often that it vibrated more than 20,000 times per second. You might be able to see the skin vibrating (just), but you certainly couldn't hear it. No matter how hard you hit the drum, you wouldn't hear a sound. The drum would still be transmitting sound waves, but your ears wouldn't be able to recognize them. Bats, dogs, dolphins, and moths might well hear them, however. Sounds this like, with frequencies beyond the range of human hearing, are examples of ultrasound.

Infrasonics, vibrational or stress waves in elastic media, having a frequency below those of sound waves that can be detected by the human ear—i.e., below 20 hertz. The range of frequencies extends down to geologic vibrations that complete one cycle in 100 seconds or longer.

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Describe in your own words, why a balloon, after it has been rubbed on a sweater, floats back towards the sweater when released.
MrRissso [65]

Explanation:

By rubbing the balloon on a sweater, you can transfer negative charges onto the surface of the balloon

8 0
2 years ago
A radioactive isotope, 14C decays to become 14N. After a time period of about 6,000 years, only about 12.5% of an original sampl
satela [25.4K]

Answer:

2000 years

Explanation:

A radioactive molecule will continuously decay and turn into another molecule. This nature of the radioactive molecule makes them can be used to estimate the age of an object. Half-life is the unit of time needed for radioactive molecules to decay to half of its mass. The formula for the mass remaining will be:

N(t)= N_{0} (\frac{1}{2})^{\frac{t}{t_{1/2} } }

Where

N(t)= number of the molecule remains

N0= number of molecule initially

t= time elapsed

t1/2= half time

We have all variable besides the half time, the calculation will be:

N(t)= N_{0} (\frac{1}{2})^{\frac{t}{t_{1/2} } }

0.125= 1 (\frac{1}{2})^{\frac{6000}{t_{1/2} } }

(\frac{1}{8})= (\frac{1}{2})^{\frac{6000}{t_{1/2} } }

(\frac{1}{2})^3= (\frac{1}{2})^{\frac{6000}{t_{1/2} } }

3= 6000/ (t1/2)

t1/2= 6000/3= 2000

The half-life is 2000 years

8 0
3 years ago
You have been working to develop a new fictitious compound in the lab. Determine the amount in units of moles​ [mol] of 40 grams
Serhud [2]

Answer : The moles of given compound is, 0.064 mole

Explanation : Given,

Mass of given compound = 40 g

Atomic mass of X = 50 amu

Atomic mass of Y = 45 amu

Atomic mass of Z = 10 amu

First we have to calculate the molar mass of given compound.

The given compound formula is, X_5Y_7Z_6

Molar mass of X_5Y_7Z_6 = (5 × Atomic mass of X) + (7 × Atomic mass of Y) + (6 × Atomic mass of Z)

Molar mass of X_5Y_7Z_6 = (5 × 50) + (7 × 45) + (6 × 10) = 625 g/mol

Now we have to calculate the moles of given compound.

\text{Moles of given compound}=\frac{\text{Mass of given compound}}{\text{Molar mass of given compound}}

\text{Moles of given compound}=\frac{40g}{625g/mol}

\text{Moles of given compound}=0.064mol

Thus, the moles of given compound is, 0.064 mole

6 0
4 years ago
During mitosis, this structure moves individual chromosomes?
stiv31 [10]

Answer:

Anaphase

Explanation:

Two separate classes of movements occur during anaphase. During the first part of anaphase, the kinetochore microtubules shorten, and the chromosomes move toward the spindle poles. During the second part of anaphase, the spindle poles separate as the non-kinetochore microtubules move past each other.

3 0
3 years ago
HELP FAST PLS !!!!!!!!!!!!!!!!
miv72 [106K]

Answer:

The Peruvian area of the jungle, living in the high trees is the monkey's habitat.

(I'm not fully sure what a niche is) but:

Feeding on hazelnuts and scavenging for food along the jungle floor is the monkey's niche.

Explanation:

I really hope I was able to help!

Good luck and have a great day :)

4 0
3 years ago
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