a. Group 2
b. Metal
a. The current highest numbered element known is Oganesson with an atomic number of 118 and it's the last period 7 element in group 18 (Noble gases). The hypothetical element number 120, would be the 2nd element in period 8 and the described electron configuration matches other group 2 elements such as Beryllium, Magnesium, Calcium, Strontium, Barium, and Radium.
b. The hypothetical element would be quite similar to the other group 2 elements which are the alkaline earth metals. The element would be expected to be a bit more reactive than Radium.
Answer:
1200 mL
Explanation:
Step 1:
Data obtained from the question. This includes the following:
Initial volume (V1) = 400 mL.
Initial pressure (P1) = 600 mmHg.
Final volume (V2) =..?
Final pressure (P2) = 200 mmHg
Step 2:
Determination of the final volume i.e the new volume of the gas.
Considering the question given, we understood that the temperature is constant. Therefore the gas is obeying Boyle's law. Using the Boyle's law equation, the new volume is obtained as follow:
P1V1 = P2V2
600 x 400 = 200 x V2
Divide both side by 200
V2 = (600 x 400) /200
V2 = 1200 mL
Therefore, the new volume of the gas is 1200 mL.
Answer:
FLASK B WHICH CONTAINS CO2 HAS THE HIGHEST NUMBER OF MOLECULES AS IT CONTAINS THE HIGHEST MOLECULAR MASS OF 44 G/MOL.
Explanation:
Flask A contains CH4
Flask B contaims CO2
Flask C contains N2
To know the flask containing the largest number of molecules, we find the molar mass of the molecules in the flask and the largest is the one with the highest number of the relative molecular mass.
Molecular Mass of CH4 (C = 12, H =1) = ( 12 + 1*4) g/mol
= 16 g/mol
Molecular mass of CO2 (C= 12, 0= 16) = (12 + 16*2) g/mol
= 12 + 32 g/mol
= 44 g/mol
Molecular mass of N2 (N=14) = 14 * 2 g/mol
= 28 g/mol
Hence, the flask with the largest number of molecules is the flask with the highest relative molecular mass. The highest molecular mass is 44 g/mol and it is for the gas CO2 in Flask B.
So therefore, Flask B has the highest number of molecules in it.
First, we need to find the atomic mass of
.
According to the periodic table:
The atomic mass of Carbon = C = 12.01
The atomic mass of Hydrogen = H = 1.008
The atomic mass of Oxygen = O = 16
As there are 6 Carbons, 12 Hydrogens and 6 Oxygens, therefore:
The
molar mass of
= 6 * 12.01 + 12 * 1.008 + 6 * 16
The
molar mass of
= 180.156
grams/moleNow that we have the molar mass of
, we can find the grams of glucose by using:
mass(of glucose in grams) = moles(of glucose given in moles) * molar mass(in grams/mole)
Therefore,
mass(of glucose in grams) = 2.47 * 180.156
mass(of glucose in grams = 444.99 grams
Ans: Mass of glucose in grams in 2.47 moles =
444.99 grams
-i