Correct answer is C..................
We need to solve x+2y=11 for x
Let's start by adding -2y to both sides
x+2y -2y = 11-2y
x= -2y+11
Now substitute -2y+11 for x in x-2y =-1
x-2y=-1
-2y+11-2y=-1
-4y+11=-1
Add -11 to both sides
-4y+11-11=-1-11
-4y=-12
Divide both sides by -4
-4y/-4 = -12/-4
y= 3
Substitute 3 for y in x=-2y+11
x= -2y+11
x = (-2)(3)+11
x=-6+11
x=5
The answer is x=5 and y=3
(5,3)
I hope that's help:)
X² + 1 = 0
=> (x+1)² - 2x = 0
=> x+1 = √(2x)
or x - √(2x) + 1 = 0
Now take y=√x
So, the equation changes to
y² - y√2 + 1 = 0
By quadratic formula, we get:-
y = [√2 ± √(2–4)]/2
or √x = (√2 ± i√2)/2 or (1 ± i)/√2 [by cancelling the √2 in numerator and denominator and ‘i' is a imaginary number with value √(-1)]
or x = [(1 ± i)²]/2
So roots are [(1+i)²]/2 and [(1 - i)²]/2
Thus we got two roots but in complex plane. If you put this values in the formula for formation of quadratic equation, that is x²+(a+b)x - ab where a and b are roots of the equation, you will get the equation
x² + 1 = 0 back again
So it’s x=1 or x=-1
First simplify 3x + 12 - 6x to -3x - 12
Next subtract 12 from both sides
Next subtract -9 - 12 and that would be -21
Next divide both sides by -3
Next lets simplify the fraction -21/-3 into 21/3 since those two negatives make a positive.
Lastly simplify the fraction 21/3 to get the answer.
Answer: x ≥ 7
Yea me ether did you ever find the answer
