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Veronika [31]
3 years ago
9

Linh builds a circuit from the diagram shown. Which bulb could Linh remove from the circuit to make all of the other bulbs stop

shining?
1

2

3

4

Physics
2 answers:
LenKa [72]3 years ago
4 0

Answer:

4

Explanation:

In order for the current to continue flowing through the circuit (and for the bulbs to continue shining), there must be a closed path containing the battery where current can flow. Let's see the effect of removing each bulb on the circuit:

- 1: when removing bulb 1 only, the current can still flow through the path battery-bulb 3- bulb 4

- 2: when removing bulb 2 only, the current can still flow through the path battery-bulb 3- bulb 4

- 3: when removing bulb 3 only, the current can still flow through the path battery-bulb 1-bulb 2- bulb 4

- 4: when removing bulb 4 only, the current can no longer flow. In fact, there is no closed path that contains the battery now, so the current will not flow and all the bulbs will stop shining.

il63 [147K]3 years ago
3 0

Answer:

4

Explanation:

It is a parrallel circuit

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Answer:

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Explanation:

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5 0
2 years ago
Prove: <br>1) p=dhg <br>.........<br>​
Lilit [14]

Explanation:

P = F/A

P = mg/A [ since F = mg ]

P = Vdg/A [ since m = Vd ]

P = Ahdg/A [ since V = Ah ]

P = hdg

6 0
3 years ago
(b) During one day, 250 kg of water is pumped through
ser-zykov [4K]

Answer: The energy incident on the solar panel during that day is 9.24 \times 10^{7} J.

Explanation:

Given: Mass = 250 kg

Initial temperature = 16^{o}C

Final temperature = 38^{o}C

Specific heat capacity = 4200 J/kg^{o}C

Formula used to calculate the energy is as follows.

q = m \times C \times (T_{2} - T_{1})

where,

q = heat energy

m = mass of substance

C = specific heat capacity

T_{1} = initial temperature

T_{2} = final temperature

Substitute the values into above formula as follows.

q = 250 kg \times 4200 J/kg^{o}C \times (38 - 16)^{o}C\\= 250 kg \times 4200 J/kg^{o}C \times 22^{o}C

As it is given that water absorbs 25% of the energy incident on the solar panel. Hence, energy incident on the solar panel can be calculated as follows.

\frac{25}{100} \times q = 250 kg \times 4200 J/kg^{o}C \times 22^{o}C\\q = 9.24 \times 10^{7} J

Thus, we can conclude that the energy incident on the solar panel during that day is 9.24 \times 10^{7} J.

4 0
2 years ago
Phyllis is calculating the path of a space probe that will travel to Pluto. On the way to Pluto, the probe will pass Mars, Satur
inysia [295]

Answer:

Jupiter

Explanation:

4 0
3 years ago
Read 2 more answers
FREE BRAINLIEST! if you can answer this correctly ill give you brainliest and answer some of the questions you have posted :) th
Gala2k [10]

b) accelerate to the left as much more pressure is pulling it in that direction and on the right however , there is less force .

4 0
3 years ago
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