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dimulka [17.4K]
2 years ago
11

Freeee Poinntssss 100!!!!!! Hi how you doin?

Engineering
2 answers:
Andreas93 [3]2 years ago
6 0
Thank u very much , im doin good wby :)
Zinaida [17]2 years ago
3 0

Answer:

Explanation:

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Write a modular program that finds the equation, area, and circumference of a circle, given the coordinates of the center of the
Semenov [28]

Answer:

Explanation:

#include <bits/stdc++.h>

#include <iostream>

#include <string>

#include <cmath>

using namespace std;

//this function reads the cooridnates of Center from the user

//parameteres are pointer variables of Cx,Cy

//it does not return anything and stores coordinates at given addresses of Cx,Cy

void readCenter(int *Cx,int *Cy)

{

string cooridnates;

cout << "Enter the x and y cooridnates of the centre of the circle separated by comma: " ;

getline(cin,cooridnates);//reading inputs

//convering string ot integer

string x = cooridnates.substr(0, cooridnates.find(","));

string y = cooridnates.substr(cooridnates.find(",")+1);

*Cx=stoi(x);

*Cy=stoi(y);

}

//this function reads the cooridnates of Point from the user

//parameteres are pointer variables of Px,Py

//it does not return anything and stores coordinates at given addresses of Px,Py

void readPoint(int *Px,int *Py)

{

string cooridnates;

cout << "Enter the x and y cooridnates of a point on the circle separated by comma: " ;

getline(cin,cooridnates);//reading inputs

//convering string ot integer

string x = cooridnates.substr(0, cooridnates.find(","));

string y = cooridnates.substr(cooridnates.find(",")+1);

*Px=stoi(x);

*Py=stoi(y);

}

double findArea(double radius)

{

double pi=acos(-1);

return pi*pow(radius,2);

}

double findCircum(double radius)

{

double pi=acos(-1);

return 2*pi*radius;

}

int main()

{

int Cx,Cy;

int Px,Py;

readCenter(&Px,&Py);

readPoint(&Cx,&Cy);

double radius=sqrt(pow((Px-Cx),2)+pow((Py-Cy),2));

cout<<"The circle has an area of "<<findArea(radius)<<" sqaure units\n";

cout<<"The circle has a Circumference of "<<findCircum(radius)<<" units";

return 0;

}

3 0
3 years ago
A shaft is made of an aluminum alloy having an allowable shear stress of τallow = 100 MPa. If the diameter of the shaft is 100 m
Elanso [62]

Answer:

A shaft is made of an aluminum alloy having an allowable shear stress of T_allow = 100 MPa. If the diameter of the shaft is 100 mm, determine the maximum torque T that can be transmitted.

Explanation:

8 0
3 years ago
Read 2 more answers
What is the major drawback to use whiskers as a dispersed agents in composites? a)- High price b)- Large length to diameter rati
artcher [175]

Answer: C) a&c

Explanation: Composite materials are the materials which are made up of the two or more material of different properties.They are usually having properties like high hardness,low in density,no dissolving into each other etc. Whiskers as a dispersing agent in composite materials are usually not preferred because they are expensive as well as they are not easy to disperse in the composite material.Thus option (c) is the correct answer.

7 0
3 years ago
Do you understand entropy? Why the concept of entropy is difficult to engineering students?
Darya [45]

Answer:

Entropy:

  Entropy is the measure of randomness of system.In other words the entropy is the measurement of tendency of system towards the disorder.

The concept of entropy arise from second law of thermodynamics.It is given as follows

ds=\int \dfrac{dQ}{T}

Entropy is a extensive property of system .

Entropy of universe = Entropy of system + Entropy of surrounding.

The entropy of the system can be zero,positive and negative.But entropy of the surrounding can not be negative,but it can be zero or positive.

Actually the concept of entropy is difficult to understand because we can not visualize because it is not like beam and like rods.Only we have to  realize that there is entropy.

4 0
3 years ago
The wall of drying oven is constructed by sandwiching insulation material of thermal conductivity k = 0.05 W/m°K between thin me
masha68 [24]

Answer:

86 mm

Explanation:

From the attached thermal circuit diagram, equation for i-nodes will be

\frac {T_ \infty, i-T_{i}}{ R^{"}_{cv, i}} + \frac {T_{o}-T_{i}}{ R^{"}_{cd}} + q_{rad} = 0 Equation 1

Similarly, the equation for outer node “o” will be

\frac {T_{ i}-T_{o}}{ R^{"}_{cd}} + \frac {T_{\infty, o} -T_{o}}{ R^{"}_{cv, o}} = 0 Equation 2

The conventive thermal resistance in i-node will be

R^{"}_{cv, i}= \frac {1}{h_{i}}= \frac {1}{30}= 0.033 m^{2}K/w Equation 3

The conventive hermal resistance per unit area is

R^{"}_{cv, o}= \frac {1}{h_{o}}= \frac {1}{10}= 0.100 m^{2}K/w Equation 4

The conductive thermal resistance per unit area is

R^{"}_{cd}= \frac {L}{K}= \frac {L}{0.05} m^{2}K/w Equation 5

Since q_{rad}  is given as 100, T_{o}  is 40 T_ \infty  is 300 T_{\infty, o}  is 25  

Substituting the values in equations 3,4 and 5 into equations 1 and 2 we obtain

\frac {300-T_{i}}{0.033} +\frac {40-T_{i}}{L/0.05} +100=0  Equation 6

\frac {T_{ i}-40}{L/0.05}+ \frac {25-40}{0.100}=0

T_{i}-40= \frac {L}{0.05}*150

T_{i}-40=3000L

T_{i}=3000L+40 Equation 7

From equation 6 we can substitute wherever there’s T_{i} with 3000L+40 as seen in equation 7 hence we obtain

\frac {300- (3000L+40)}{0.033} + \frac {40- (3000L+40)}{L/0.05}+100=0

The above can be simplified to be

\frac {260-3000L}{0.033}+ \frac {(-3000L)}{L/0.05}+100=0

\frac {260-3000L}{0.033}=50

-3000L=1.665-260

L= \frac {-258.33}{-3000}=0.086*10^{-3}m= 86mm

Therefore, insulation thickness is 86mm

8 0
3 years ago
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