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dimulka [17.4K]
3 years ago
11

Freeee Poinntssss 100!!!!!! Hi how you doin?

Engineering
2 answers:
Andreas93 [3]3 years ago
6 0
Thank u very much , im doin good wby :)
Zinaida [17]3 years ago
3 0

Answer:

Explanation:

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Calculate the frequencies (in Hz) for the ten lowest modes of a rigid-wall room of dimensions 2.59m x 2.42m x 2.82m (i.e., find
Digiron [165]

Answer:

For This Answer Please See the Attached File.

Explanation:

Download pdf
3 0
3 years ago
What substance does light travel through before putting water in the cup
torisob [31]
Bend surface in water! Hopefully this helps, I looked it up!

6 0
3 years ago
The pump of a water distribution system is powered by a 6-kW electric motor whose efficiency is 95 percent. The water flow rate
Sonja [21]

Answer:

a) Mechanical efficiency (\varepsilon)=63.15%  b) Temperature rise= 0.028ºC

Explanation:

For the item a) you have to define the mechanical power introduced (Wmec) to the system and the power transferred to the water (Pw).

The power input (electric motor) is equal to the motor power multiplied by the efficiency. Thus, Wmec=0.95*6kW=5.7 kW.

Then, the power transferred (Pw) to the fluid is equal to the flow rate (Q) multiplied by the pressure jump \Delta P. So P_W = Q*\Delta P=0.018m^3/s * 200x10^3 Pa=3600W.

The efficiency is defined as the ratio between the output energy and the input energy. Then, the mechanical efficiency is \varepsilon=3.6kW/5.7kW=0.6315=63.15\%

For the b) item you have to consider that the inefficiency goes to the fluid as heat. So it is necessary to use the equation of the heat capacity but in a "flux" way. Calling <em>H</em> to the heat transfered to the fluid, the specif heat of the water and \rho the density of the water:

[tex]H=(5.7-3.6) kW=\rho*Q*c*\Delta T=1000kg/m^3*0.018m^3/s*4186J/(kg \ºC)*\Delta T[/tex]

Finally, the temperature rise is:

\Delta T=2100/75348 \ºC=0.028 \ºC

7 0
3 years ago
Q1) Determine the force in each member of the
Sever21 [200]

Answer:

  • CD = DE = DF = 0
  • BC = CE = 15 N tension
  • FA = 15 N compression
  • CF = 15√2 N compression
  • BF = 25 N tension
  • BG = 55/2 N tension
  • AB = (25√5)/2 N compression

Explanation:

The only vertical force that can be applied at joint D is that of link CD. Since joint D is stationary, there must be no vertical force. Hence the force in link CD must be zero, as must the force in link DE.

At joint E, the only horizontal force is that applied by link EF, so it, too, must be zero.

Then link CE has 15 N tension.

The downward force in CE must be balanced by an upward force in CF. Of that force, only 1/√2 of it will be vertical, so the force in CF is a compression of 15√2 N.

In order for the horizontal forces at C to be balanced the 15 N horizontal compression in CF must be balanced by a 15 N tension in BC.

At joint F, the 15 N horizontal compression in CF must be balanced by a 15 N compression in FA. CF contributes a downward force of 15 N at joint F. Together with the external load of 10 N, the total downward force at F is 25 N. Then the tension in BF must be 25 N to balance that.

At joint B, the 25 N downward vertical force in BF must be balanced by the vertical component of the compressive force in AB. That component is 2/√5 of the total force in AB, which must be a compression of 25√5/2 N.

The <em>horizontal</em> forces at joint B include the 15 N tension in BC and the 25/2 N compression in AB. These are balanced by a (25/2+15) N = 55/2 N tension in BG.

In summary, the link forces are ...

  • (25√5)/2 N compression in AB
  • 15 N tension in BC
  • 25 N tension in BF
  • 0 N in CD, DE, and EF
  • 15 N tension in CE
  • 15√2 compression in CF
  • 15 N compression in FA

_____

Note that the forces at the pins of G and A are in accordance with those that give a net torque about those point of 0, serving as a check on the above calculations.

8 0
3 years ago
The tolerance for a geometric can be easily identified by reading the _________.
baherus [9]

Answer:

C

Explanation:

4 0
3 years ago
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