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nydimaria [60]
3 years ago
13

A 6.0 C charge is placed at the origin and a second charge is placed on the x-axis at x 0.3m. If the resulting electric force on

the second charge is 5.4 N in the positive x-direction, what is the value of its charge?
Physics
1 answer:
almond37 [142]3 years ago
8 0

Answer:

9 x 10^-12 c

Explanation:

q1 = 6 C

d = 0.3 m

q2 = ?

F = 5.4 N

As te force on the second charge is in the positive X axis direction so the charge on the second particle is positive in nature.

F = K q1 q2 / d^2

5.4 = ( 9 x 10^9 x 6 x q2) / (0.3 x 0.3)

5.4 x 0.3 x 0.3 = 54 x 10^9 x q2

q2 = 9 x 10^-12 C

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Explanation:

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Mastering Problems
lesya692 [45]

Answer:

C , E , A , D , B

Explanation:

We evaluate the accelerations for each case, using the formula: a = (vf - vi) / t

A)  a = (10.3 - 0.5 ) / 1 = 9.8 m/s^2  --> magnitude: 9.8 m/s^2

B)  a = (0 - 20) / 1 = - 20 m/s^2  -->  magnitude : 20 m/s^2

C)  a = (0.02 - 0.004) / 1 = 0.016 m/s^2 -->  magnitude : 0.016  m/s^2

D)  a = (4.3 - 0) / 0.4 = 10.75 m/s^2  -->  magnitude : 10.75 m/s^2

E)  a = (1 - 2) / 8.3 = - 0.12 m/s^2  -->  magnitude: 0.12 m/s^2

Then, comparing magnitudes from least to greatest:

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7 0
3 years ago
A 6.4-N force pulls horizontally on a 1.5-kg block that slides on a smooth horizontal surface. This block is connected by a hori
Elena L [17]

-- Although it's not explicitly stated in the question,we have to assume that
the surface is frictionless.  I guess that's what "smooth" means.

-- The total mass of both blocks is (1.5 + 0.93) = 2.43 kg. Since they're
connected to each other (by the string), 2.43 kg is the mass you're pulling.

-- Your force is 6.4 N.
                                    Acceleration = (force)/(mass) = 6.4/2.43 m/s²<em>
                                                                 </em>
That's about  <em>2.634 m/s²</em>  <em>

</em>
(I'm going to keep the fraction form handy, because the acceleration has to be
used for the next part of the question, so we'll need it as accurate as possible.)

-- Both blocks accelerate at the same rate. So the force on the rear block (m₂) is

       Force = (mass) x (acceleration) = (0.93) x (6.4/2.43) = <em>2.45 N</em>.

That's the force that's accelerating the little block, so that must be the tension
in the string.


7 0
3 years ago
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