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nydimaria [60]
3 years ago
13

A 6.0 C charge is placed at the origin and a second charge is placed on the x-axis at x 0.3m. If the resulting electric force on

the second charge is 5.4 N in the positive x-direction, what is the value of its charge?
Physics
1 answer:
almond37 [142]3 years ago
8 0

Answer:

9 x 10^-12 c

Explanation:

q1 = 6 C

d = 0.3 m

q2 = ?

F = 5.4 N

As te force on the second charge is in the positive X axis direction so the charge on the second particle is positive in nature.

F = K q1 q2 / d^2

5.4 = ( 9 x 10^9 x 6 x q2) / (0.3 x 0.3)

5.4 x 0.3 x 0.3 = 54 x 10^9 x q2

q2 = 9 x 10^-12 C

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Solve the equation x=3logy2 for y.
melisa1 [442]

X = 3 · log(Y²)

X = 3 · 2·log(Y)

X/6 = log(Y)

10^(X/6) = 10^log(Y)

Y = 10^(X/6)

6 0
3 years ago
Read 2 more answers
Standing waves can ruin the acoustics of a concert hall if there is excessive reflection of the sound waves that the performers
Dmitrij [34]

Answer:

The answer to the questions is;

In terms of standing waves, the listener moves from a location with high amplitude to one with lower amplitude or vibration (anti-node to node)

The distance 4.1 cm is equivalent to λ/4

Explanation:

For standing waves we have is a stationary wave comprising of two opposite direction moving waves that have equal amplitude and frequency, resulting in the superimposition of the waves. As such certain points are fixed along the wave path that is the peaks amplitude of the wave oscillation is constant at a particular point. A node occurring at a point and an anti-node occurring at another fixed point

When the listener moves 4.1 cm he or she has left the anti-node to the node hence the faintness of the sound

The distance from the node to the anti-node is 1/4 wavelength, or 1/4×λ

Therefore 4.1 cm is λ/4

6 0
3 years ago
In the writing of ionic chemical formulas, what factor is "crossed over" in the crossover rule?
Aleks04 [339]

In the writing of ionic chemical formulas the value of each ion's charge is crossed over in the crossover rule.

Rules for naming Ionic compounds

  • Frist Rule
    The cation (element with a negative charge) is written first in the name then the anion(element with a positive charge) is written second in the name.
  • Second rule
    When the formula unit contains two or more of the same polyatomic ion, that ion is written in parentheses with the subscript written outside the parentheses.
    Example: Sodium carbonate is written as Na₂CO₃ not Na₂(CO)₃
  • Third rule
    If the cation is a metal ion with a fixed charge then the name of the cation will remain the same as the (neutral) element from which it is derived (Example: Na+ will be sodium).
    If the cation is a metal ion with a variable charge, the charge on the cation is indicated using a Roman numeral, in parentheses, immediately following the name of the cation (example: Fe³⁺ = iron(III)).
  • Fourth rule
    If the anion is a monatomic ion, the anion is named by adding the suffix <em>-ide</em> to the root of the element name (example: F = Fluoride).

The oxidation state of each ion is also important, thus in the crossover rule, the value of each ion's charge is crossed over.

Learn more about chemical formulas here:

<u>brainly.com/question/11995171</u>

#SPJ4

3 0
2 years ago
Which statement explains the polarity of a water molecule?
timofeeve [1]

Answer:

D. The oxygen side is partially negative because electrons are pulled toward the oxygen side.

Explanation:

The water molecule is polar by the virtue of covalent bonds and the hydrogen bonds within and between its molecule.

The oxygen side is partially negative because the electrons are pulled toward the oxygen side.

Between oxygen and hydrogen that makes up the water molecule, oxygen is more electronegative.

An electronegative atom has more affinity for electrons. Since the electrons in the molecule of water is shared between hydrogen and oxygen, the more electronegative specie which is water draws the electron more to itself.

This leaves a net negative charge on the oxygen atom.

8 0
3 years ago
what is the acceleration of each body of mass 5kg rests on a frictionless table and is connected to a cable that passes over a p
Oksanka [162]

Answer:

6.53 m/s²

Explanation:

Let m₁ = 5 kg and m₂ = 10 kg. The figure is attached and free body diagrams of the objects are also attached.

Both objects (m₁ and m₂) have the same magnitude of acceleration(a). Let g be the acceleration due to gravity = 9.8 m/s². Hence:

T = m₁a               (1)

m₂g - T = m₂a    (2)

substituting T = m₁a in equation 2:

m₂g - m₁a = m₂a

m₂a + m₁a = m₂g

a(m₁ + m₂) = m₂g

a = m₂g / (m₁ + m₂)

a = (10 kg * 9.8 m/s²) / (10 kg + 5 kg) = 6.53 m/s²

Both objects have an acceleration of 6.53 m/s²

8 0
3 years ago
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