Question

What is the frequency of a photon of light (in Hz) that has an energy of 2.50 x 10-18 J?

Answer 1

Answer:

The answer is

$3.77 \times {10}^{15} \: \: \: Hz$

Explanation:

The frequency of the photon can be found by using the formula

$f = \frac{E}{h}$

where

E is the energy

f is the frequency

h is the Planck's constant which is

6.626 × 10-³⁴ Js

From the question

E = 2.50 × 10^-18 J

So we have

$f = \frac{2.50 \times {10}^{ - 18} }{6.626 \times {10}^{ - 34} }$

We have the final answer as

$3.77 \times {10}^{15} \: \: \: Hz$

Hope this helps you